Correct answer is B
25 characters
Q1 of company A = 2.5
Q3 of company A = 8
Interquatile range = (Q3 - Q1)/2 = (8 - 2.5)/2 = 5.5/2 = 2.75
Q1 of company B = 2
Q3 of company B = 5.5
Interquatile range = (5.5 - 2)/2 = 3.5/2 = 1.75
Therefore, t<span>he interquartile range for Company A employees is 2 more than the interquartile range for Company B employees.</span>
Answer:
There are 0.005 hundreds in 5/10.
Step-by-step explanation:
Claire drew model of 5/10
We want to know how many hundreds are in 5/10.
Let us use an obvious example.
There are three 2's in 6 right?
Suppose we didn't know this, and we are told to find how many 2's are in 6, we get this by representing this in an algebraic expression as:
There are x 2's in 6. This can be written as
2x = 6
Solving for x, by dividing both sides by 2, we have the number of 2's that are in 6.
x = 6/2 = 3.
Now, to our work
We want to find how many hundreds are in 5/10. We solve the equation
100x = 5/10
x = 5/1000 = 0.005
There are 0.005 hundreds in 5/10.
There is 45.9 inches of snow for the whole year
so average / month = 45.9 / 12 = 3.825 inches
What is the third quartile of this data set 20,21,24,25,28,29,35,36,37,43,44
SashulF [63]
Answer:
37
Step-by-step explanation:
The data set is in ascending order, thus the median is the middle value of the data set.
median = 29
The third quartile is the middle value of the data to the right of the median
= 37
