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Varvara68 [4.7K]
4 years ago
6

How many molecules are in 3.40 mol He?

Chemistry
1 answer:
shutvik [7]4 years ago
8 0

Answer:

20.5 × 10²³ molecules of He

Explanation:

Given data:

Number of moles of He = 3.40 mol

Number of molecules of He = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

For 3.40 moles of He:

3.40 mol × 6.022 × 10²³ molecules

20.5 × 10²³ molecules of He

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\Delta G^o_{rxn}=[(2\times (-16.45))]-[(1\times (0))+(3\times (0))]\\\\\Delta G^o_{rxn}=-32.9kJ/mol

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\Delta G^o=-RT\ln K_{eq}

where,

\Delta G^o = standard Gibbs free energy = -32.9 kJ/mol = -35900 J/mol  (Conversion factor: 1 kJ = 1000 J )

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T = temperature = 25^oC=[273+25]K=298K

K_{eq} = equilibrium constant at 25°C = ?

Putting values in above equation, we get:

-32900J/mol=-(8.314J/Kmol)\times 298K\times \ln K_{eq}\\\\K_{eq}=e^{13.279}=5.85\times 10^{5}

Hence, the equilibrium constant for this reaction is 5.85\times 10^{5}

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