36) HCl(aq)+KOH(aq)⇒H₂O(l)+KCl(aq)
37) You can use the equation M₁V₁=M₂V₂
M₁=concentration of acid
V₁=volume of acid in orginal solution
M₂=concentration of base
V₂= the volume of based used to neutralize the acid
M₁=(0.150M KOH x 0.0185L KOH)/0.025L HCl
M₁=0.111M HCl
This equation works since we no based off of the formula in question 36 that 1 mole of KOH will neutralize 1 mole of HCl and <span>M₂V₂ is equal to the moles KOH which means it needs to equal M</span>₁V₁ since that is the number of moles HCl. (if moles HCl did not equal moles KOH the solution would not be neutralized).
Answer:
if its under 7 then it's an acid you neek over 7 is alkaline
Answer:
The energy produced equals 140.760 kJ
Explanation:
The relation between power, current and voltage is

Applying the given values in the relation above we get

Now Since 
Again applying the calculated values we get

Given is the specific heat of water equal to 4.18 Joule per gram per *C.
This means to raise the temperature of 1 g of water by 1 degree Celsius we need 4.18 joule of energy.
Now, look at the question. We are asked that how much amount of energy would be required to raise the temperature of 25 g of water by (54-50) = 4 degree celsius.
To do so we have formula
Q = m C (temperature difference)
Have a look at pic for answer