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Ket [755]
3 years ago
14

Why is drinking urine unhealthy? whats in it?

Chemistry
2 answers:
Kryger [21]3 years ago
7 0
This is by far probably the best question I've answered all day.
It's not unhealthy to drink it.
Urine consists of 95% water and 5% nutrients
Aneli [31]3 years ago
5 0
Because it has all toxic substances which having harmful effect.
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Blank a long narrow Stepside value that forms the deepest part of the ocean ​
elixir [45]

Answer:

The answer is a trench

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3 years ago
List science of kinesiology that interest you? Why there science interest you
Mkey [24]

Answer:

The study of the human body as a machine for the performance of work has its foundations in three major areas of study—namely, mechanics, anatomy, and physiology; more specifically, biomechanics, musculoskeletal anatomy, and neuromuscular physiology. Explanation:

5 0
3 years ago
1.00 mole of an ideal monoatomic gas at STP first undergoes isothermal expansion so that the volume at b is 2.5 times the volume
MrRa [10]

Answer:

the pressure at c = 0.27 atm

Explanation:

Given that:

number of moles (n) = 1.0 moles

Value of gamma in the monoatomic gas (γ) = 5/3

During an isothermal expansion, the volume at b is = 2.5 times the volume at a ; this implies that:

V_b = 2.5 V_a

∴ To calculate  the pressure at c from a; the process is adiabatic compression; so we apply:

P_aV_a^\gamma=P_cV_c^\gamma

\frac{P_c}{P_a}=[\frac{V_a}{V_c}]^{(2/3)

\frac{P_c}{1.0 atm}=[\frac{1}{2.5}]^{(2/3)

P_c=0.27 atm

Thus, the pressure at c = 0.27 atm

8 0
3 years ago
A sample of an unknown compound is vaporized at . The gas produced has a volume of at a pressure of , and it weighs . Assuming t
Likurg_2 [28]

Answer:

The answer is "34 \ \frac{g}{mol}"

Explanation:

Please find the complete question in the attached file.

Formula:

\to PV = nRT\\\\n = \frac{mass}{MW} \\\\PV = \frac{mRT}{MW}\\\\MW = \frac{mRT}{(PV)}\\\\MW = \frac{(0.941)(0.082)(150+273)}{(1 \times 0.96)}

        = \frac{(0.941)(0.082)(423)}{(0.96)} \\\\= \frac{32.639526}{(0.96)} \\\\= 33.9995062\ \ \ or \ \ \ 34 \ \frac{g}{mol}

8 0
3 years ago
How many formula units make up 24.2 g of magnesium chloride (MgCl2)?<br><br> Help!!
NNADVOKAT [17]

Answer:

Approximately 1.53 \times 10^{23} formula units (0.254\; \rm mol).

Explanation:

Refer to a modern periodic table for the relative atomic mass of magnesium (\rm Mg) and chlorine (\rm Cl):

  • \rm Mg: 24.305.
  • \rm Cl: 35.45.

In other words, the mass of 1\; \rm mol of \rm Mg atoms would be (approximately) 24.305\; \rm g.

Likewise, the mass of 1\; \rm mol of \rm Cl atoms would be approximately 35.45\; \rm g.

One formula unit of the ionic compound \rm MgCl_{2} includes exactly as many atoms as there are in the given formula. The formula mass of a compound is the mass of 1\; \rm mol of the formula units of this compound.

The formula \rm MgCl_{2} includes one \rm Mg atom and two \rm Cl atoms.

Hence, every formula unit of \rm MgCl_{2} \! would include the same number of atoms: one \rm Mg\! atom and two \rm Cl\! atoms. There would be 1\; \rm mol of \rm Mg atoms and 2\; \rm mol of \rm Cl atoms in 1\; \rm mol\! of \rm MgCl_{2} formula units.

Thus, the mass of 1\; \rm mol\! of \rm MgCl_{2} formula units would be equal to the mass of 1\; \rm mol of \rm Mg atoms plus the mass of 2\; \rm mol of \rm Cl atoms. (The mass of 1\; \rm mol\!\! of each atom could be found from the relative atomic mass of each element.)

\begin{aligned}& M({\rm MgCl_{2}}) \\ =\; & 24.305\; {\rm g \cdot mol^{-1}} + 2\times {\rm 35.45 \; \rm g \cdot mol^{-1}} \\ =\; & 95.205\; \rm g \cdot mol^{-1}\end{aligned}.

In other words, the formula mass of \rm MgCl_{2} is 95.205\; \rm g \cdot mol^{-1}.

Therefore, the number of formula units in m = 24.2\; \rm g of \rm MgCl_{2} would be:

\begin{aligned}n &= \frac{m({\rm MgCl_{2}})}{M({\rm MgCl_{2}})} \\ &= \frac{24.2\; \rm g}{95.205\; \rm g\cdot mol^{-1}} \\ & \approx 0.254\; \rm mol\end{aligned}.

Multiple n by Avogadro's Number N_{A} \approx 6.022 \times 10^{23}\; \rm mol^{-1} to estimate the number of formula units in 0.254\; \rm mol:

\begin{aligned}N &= n \cdot N_{A} \\ &\approx 0.254\; \rm mol \times 6.022 \times 10^{23}\; \rm mol^{-1} \\ &\approx 1.53\times 10^{23}\end{aligned}.

6 0
3 years ago
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