Answer:
1540.8 Joules of energy is required to bring a 30 gram crayon from room temperature, 25 degrees C, to its melting point 49 degrees C
Explanation:
Crayon is paraffin wax. The specific heat of paraffin wax is 2.14 J/g°C
As we know
Where
is the change in temperature
m is the mass of the object
c is the specific heat in J/g°C
Substituting the given values, we get -
Joules
1540.8 Joules of energy is required to bring a 30 gram crayon from room temperature, 25 degrees C, to its melting point 49 degrees C
Answer:
The Celsius scale is in general use wherever metric units have become accepted, and it is used in scientific work everywhere. Kelvin temperature scale is the base unit of thermodynamic temperature measurement in the International System (SI) of measurement
Answer:
Explanation:
The density of an object is found by dividing the mass by the volume.
The mass is 12.1 grams, but we are not given the volume. Instead, we are told that the water before is 24.2 millilitres and the water after is 28.8 millilitres.
So, the volume was taken using water displacement. We can find the volume by subtracting the initial volume from the volume after the object was added.
- v= with object - initial
- v= 28.8 mL-24.2 mL=4.6 mL
Now we know the mass and volume:
Substitute the values into the formula.
Divide.
Let's round to the nearest hundredth. The 0 in the thousandth place tells us to leave the 3.
1 milliliter is equal to 1 cubic centimer, so the density can also be written as:
The density of the rock is approximately 2.63 grams per cubic centimeter.