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loris [4]
3 years ago
9

Where is most of the mass of an atom? •

Chemistry
1 answer:
yaroslaw [1]3 years ago
6 0
B. inside the nucleus
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Calculate the number of grams of carbon dioxide produced from 6 moles of oxygen gas. List only the number of grams of carbon dio
faust18 [17]

Answer:

g CO2(g) = 264.06 g

Explanation:

  • C(s)  + O2(g) → CO2(g)

∴ moles O2(g) = 6 mol

∴ mm CO2 = 44.01 g/mol

⇒ mol CO2(g) = ( 6 mol O2(g) )×( mol CO2(g) / mol O2(g) ) = 6 mol CO2(g)

⇒ mass CO2(g) = ( 6 mol CO2(g) )×( 44.01 g/mol ) = 264.06 g CO2(g)

3 0
3 years ago
which of these statements best describes the law of conservation of mass A) when a physical or a chemical change occurs, matter
vampirchik [111]
The statement which best describes the law of conservation of mass is A) when a physical or a chemical change occurs, matter is not created or destroyed. The law states that matter cannot be created or destroyed by ordinary chemical or physical changes, which means that <span>the mass of all the components of a chemical reaction can be measured before and after the change in order prove that the mass is constant. So, keep in mind that </span><span>the mass of participating products is always the same as the mass of all the reactants.</span>
3 0
3 years ago
Read 2 more answers
Calculate ΔH o rxn for the following: CH4(g) + Cl2(g) → CCl4(l) + HCl(g)[unbalanced] ΔH o f [CH4(g)] = −74.87 kJ/mol ΔH o f [CCl
anzhelika [568]

Answer:  ΔH for the reaction is -277.4 kJ

Explanation:

The balanced chemical reaction is,

CH_4(g)+Cl_2(g)\rightarrow CCl_4(l)+HCl(g)

The expression for enthalpy change is,

\Delta H=\sum [n\times \Delta H(products)]-\sum [n\times \Delta H(reactant)]

\Delta H=[(n_{CCl_4}\times \Delta H_{CCl_4})+(n_{HCl}\times B.E_{HCl}) ]-[(n_{CH_4}\times \Delta H_{CH_4})+n_{Cl_2}\times \Delta H_{Cl_2}]

where,

n = number of moles

Now put all the given values in this expression, we get

\Delta H=[(1\times -139)+(1\times -92.31) ]-[(1\times -74.87)+(1\times 121.0]

\Delta H=-277.4kJ

Therefore, the enthalpy change for this reaction is, -277.4 kJ

4 0
3 years ago
A solution was prepared by dissolving 2.2 g of an unknown solute in 16.7 g of CCl4. A thermal analysis was performed for this so
laila [671]

Answer:

Molar mass of unknown solute is 679 g/mol

Explanation:

Let us assume that the solute is a non-electrolyte.

For a solution with non-electrolyte solute remains dissolved in it -

Depression in freezing point of solution, \Delta T_{f}=K_{f}.m

where, m is molality of solute in solution and K_{f} is cryogenoscopic constant of solvent.

Here \Delta T_{f}=(-22.9^{0}\textrm{C})-(-28.7^{0}\textrm{C})=5.8^{0}\textrm{C}

If molar mass of unknown solute is M g/mol then-

                 m=\frac{\frac{2.2}{M}}{0.0167}mol/kg

So, 5.8^{0}\textrm{C}=29.9^{0}\textrm{C}/(mol/kg)\times \frac{\frac{2.2g}{M}}{0.0167}mol/kg

so, M = 679 g/mol

4 0
3 years ago
Select the example of symbiosis, chosen from the list below that is best described by the statement shown.
ololo11 [35]

Answer:

can you show us the list

Explanation:

8 0
2 years ago
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