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loris [4]
4 years ago
9

Where is most of the mass of an atom? •

Chemistry
1 answer:
yaroslaw [1]4 years ago
6 0
B. inside the nucleus
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Krafla Volcano in Iceland,

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4 years ago
Which unit conversion allows you to convert 21.0 gallons into milliliters?
Romashka-Z-Leto [24]

79470.2mL

Explanation:

Given:

  Volume = 21gallons

  problem, convert to milliliters;

   

  gallons to milliliters

 1 liter = 1.057 quarts

1 gallon = 4 quarts

we can simply solve this by establishing and using a conversion factor of 1 ;

     

   1 gallon = 4 quarts

   1.057 quarts = 1 liter

   0.001L = 1mL

21gallons x \frac{4qt}{1gal} x \frac{1 liter}{1.057qt} x \frac{1mL }{0.001L}  = 79470.2mL

we say;

From; \frac{4qt}{1gal} x \frac{1 liter}{1.057qt} x \frac{1mL }{0.001L}

1gallon = 3784.2mL

learn more:

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8 0
3 years ago
1. A gas having the following composition is burnt under a boiler with 50% excess air.
jeka94

The composition of the stack gas are :

CH_4= 0.8713

C_3H_8 = 0.0202

CO = 0.107

<h3 /><h3>What is a mole fraction?</h3>

The ratio of the number of moles of one component of a solution or other mixture to the total number of moles representing all of the components.

Assuming 100 g of the stack gas. Calculate the mass of each species in this sample according to their percentages.

Mass of CH_4 : 70% of 100 g = 70 g

Mass of C_3H_8 : 15% of 100 g = 15 g

Mass of CO : 15% of 100 g = 15 g

Now calculate the number of moles of each species:

Number of moles of CH_4 : \frac{70 g}{16.04 g/mol} = 4.3 mole

Number of moles of C_3H_8: \frac{15 g}{144.1 g/mol} = 0.10 mole

Mass of CO : \frac{15 g}{28.01 g/mol} = 0.53 mole

Now to calculate the mole fraction of each we use the formula:

Mole fraction of CH_4: \frac{4.3}{4.935} = 0.8713

Mole fraction of C_3H_8 : \frac{0.10}{4.935} = 0.0202

Mole fraction of CO : \frac{0.53}{4.935} = 0.107

Hence, composition of the stack gas are:

CH_4 = 0.8713

C_3H_8 = 0.0202

CO = 0.107

Learn more about mole fraction here:

brainly.com/question/13135950

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3 years ago
When a substance was dissolved in water, the temperature of the water increased. This process is described as
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The correct answer will be A
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The less mass in a given volume of air the
DiKsa [7]

Answer:

The less mass in a given volume of air the  less dense the air is going to be.

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