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Stels [109]
3 years ago
10

A solution of sodium chloride is mixed with a solution of lead(II) nitrate. A precipitate of lead(II) chloride results, leaving

a solution of sodium nitrate. Into which class(es) does this reaction fit?
Chemistry
1 answer:
Law Incorporation [45]3 years ago
3 0

Answer:

Double displacement reaction

Explanation:

The chemical reaction is as follows :

NaCl + Pb(NO3)2 → PbCl + NaNO3.

Balanced equation:

Pb(NO3)2 + 2NaCl → PbCl2 + 2NaNO3

The reaction is a double displacement reaction . A double displacement reaction is a chemical reaction between compound where the cations and the anions of the 2 reactants exchange places to form a new product.

Double displacement reaction, the 2 reactants exchange ions to form new compounds. Double displacement reaction usually produce a solid precipitate. A good illustration of a double displacement reaction is

AB + CD → AD + CB.

From the reaction above the Sodium ion replace lead to from sodium nitrate while lead replace sodium to form the precipitate lead chloride.  The anions(negatively charged ions) also exchange position.  

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fe2o3 + 6hcl => 2fecl3 + 3h2o

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the point on earths surface directly above where an earthquake happen is called? a.)focus b.)epicenter c.)hypocenter d.)locus​
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For which of these processes is the value of ΔH expected to be negative?I. The temperature (of water) increases when calcium chl
Marina CMI [18]

Answer: B.) I, II, and III

Explanation:

Exothermic reactions are defined as the reactions in which energy of the product is lesser than the energy of the reactants. The total energy is released in the form of heat and \Delta H for the reaction comes out to be negative.

Endothermic reactions are defined as the reactions in which energy of the product is greater than the energy of the reactants. The total energy is absorbed in the form of heat and \Delta H for the reaction comes out to be positive.

I) The temperature (of water) increases when calcium chloride dissolves in water : Thus the reaction is exothermic and  \Delta H for the reaction comes out to be negative.

II)  Steam condenses to liquid water : The energy is released when bonds are formed when it coverts from gas to liquid and thus \Delta H for the reaction comes out to be negative.

III) Water freezes : The energy is released when bonds are formed to get converted from liquid to solid and thus \Delta H for the reaction comes out to be negative.

IV) Dry ice sublimes : The energy is absorbed when bonds are broken to get converted from solid to gas and thus \Delta H for the reaction comes out to be positive.

6 0
4 years ago
A compound contains 1.2 g of carbon, 3.2 g of oxygen and 0.2g of hydrogen. Find the formula of the compound
Karolina [17]

Answer:

The empirical formula of the compound is C_{0.504}HO_{1.008}.

Explanation:

We need to determine the empirical formula in its simplest form, where hydrogen (H) is scaled up to a mole, since it has the molar mass, and both carbon (C) and oxygen (O) are also scaled up in the same magnitude. The empirical formula is of the form:

C_{x}HO_{y}

Where x, y are the number of moles of the carbon and oxygen, respectively.

The scale factor (r), no unit, is calculated by the following formula:

r = \frac{M_{H}}{m_{H}} (1)

Where:

m_{H} - Mass of hydrogen, in grams.

M_{H} - Molar mass of hydrogen, in grams per mole.

If we know that  M_{H} = 1.008\,\frac{g}{mol} and m_{H} = 0.2\,g, then the scale factor is:

r = \frac{1.008}{0.2}

r = 5.04

The molar masses of carbon (M_{C}) and oxygen (M_{O}) are 12.011\,\frac{g}{mol} and 15.999\,\frac{g}{mol}, then, the respective numbers of moles are: (r = 5.04, m_{C} = 1.2\,g, m_{O} = 3.2\,g)

Carbon

n_{C} = \frac{r\cdot m_{C}}{M_{C}} (2)

n_{C} = \frac{(5.04)\cdot (1.2\,g)}{12.011\,\frac{g}{mol} }

n_{C} = 0.504\,moles

Oxygen

n_{O} = \frac{r\cdot m_{O}}{M_{O}} (3)

n_{O} = \frac{(5.04)\cdot (3.2\,g)}{15.999\,\frac{g}{mol} }

n_{O} = 1.008\,moles

Hence, the empirical formula of the compound is C_{0.504}HO_{1.008}.

3 0
3 years ago
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