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cluponka [151]
3 years ago
12

ould it make any difference if the methylene chloride solutioncontaining both thebasicand neutral components waswashed with 1Mso

dium hydroxiderather than 1Mhydrochloric acid? If so,what would that difference be? Would any layer separation bepossible in the new solution? Would it be possible to isolate the two components from oneanother using 1Msodium hydroxiderather than 1Mhydrochloric acid?Why or why not?Provide a balanced equation to justify your answ
Chemistry
1 answer:
Bad White [126]3 years ago
3 0

Answer:

Explanation:

No, it is ludicrous and not possible to separate and detach a basic and neutral compound by 1M NaOH in DCM. This is due to the fact that neutral compounds don't respond and react with NaOH, and NaOH itself occurs to be a base. As a result, it can't respond and react with another base to produce salt. Consequently, we simply need a corrosive component i.e an acid

So; In DCM, we can't use 1M NaOH instead of 1M HCI for isolation and separation of neutral and basic compound mixtures.

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7 0
3 years ago
Calculate the molality of a solution formed by adding 6.30 g NH4CL to 15.7 g of water
babymother [125]

Answer:

Molality = 7.5 mol/kg

Explanation:

Given data:

Mass of NH₄Cl = 6.30 g

Mass of water = 15.7 g (15.7/1000 =0.016 kg)

Molality = ?

Solution:

Formula of molality:

Molality = Moles of solute / mass of solvent in gram

Now we will first calculate the number of moles of solute( NH₄Cl )

Number of moles = mass/ molar mass

Molar mass of  NH₄Cl = 53.491 g/mol

Number of moles = 6.30 g/  53.491 g/mol

Number of moles =  0.12 mol

Now we will calculate the molality.

Molality = Moles of solute / mass of solvent in gram

Molality =  0.12 mol / 0.016 kg

Molality = 7.5 m

or        (m=mol/kg)

Molality = 7.5 mol/kg

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3 years ago
Help ASAP pleaseeee!
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Answer:

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5 0
3 years ago
Read 2 more answers
Please show all work:
Tom [10]

If 40.0 grams of magnesium is reacted with an excess of nitric acid. 3.3 g of hydrogen gas will be produced.

<h3>What is Stoichiometry ?</h3>

Stoichiometry helps us use the balanced chemical equation to measure quantitative relationships and it is to calculate the amounts of products and reactants that are given in a reaction.

<h3>What is Balanced Chemical Equation ?</h3>

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

Now we have to write the balanced equation

Mg + 2HNO₃  → Mg(NO₃)₂ + H₂

According to Stoichiometry

40.9\ \text{g Mg} \times \frac{1\ \text{mol Mg}}{24.31\ \text{g Mg}} \times \frac{1\ \text{mol}\ H_2}{1\ \text{mol Mg}} \times \frac{2.02\ g\ H_2}{1\ \text{mol}\ H_2}

= 3.3 g H₂

Thus from the above conclusion we can say that If 40.0 grams of magnesium is reacted with an excess of nitric acid. 3.3 g of hydrogen gas will be produced.

Learn more about the Stoichiometry here: brainly.com/question/16060223

#SPJ1

8 0
2 years ago
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