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Leya [2.2K]
3 years ago
12

Which is the correctly balanced equation for the reaction of rust, fe2o3, and hydrochloric acid, hcl?.

Chemistry
1 answer:
kap26 [50]3 years ago
7 0

Answer:

fe2o3 + 6hcl => 2fecl3 + 3h2o

Explanation:

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Define molecular formula and empirical formula. What are the similarities and differences between the empirical formula and mole
irga5000 [103]

<u>Explanation:</u>

Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.  

Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.  

In both the formulas, the nature of atoms remains the same but the number differs.

For Example: The molecular formula of oxalic acid is C_2H_2H_4 but the empirical formula of oxalic acid is CHO_2

To calculate the molecular formula, we need to find the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

n=\frac{\text{Molecular mass}}{\text{Empirical mass}}

The empirical mass can be calculated from empirical formula and molar mass must be known.

6 0
4 years ago
Data and evidence are interchangeable in science. True or false?
Elodia [21]
True because if an old theory finds new information that can be changed if it’s different then the original material
6 0
3 years ago
You are throwing a pizza party for 15 people and figure that each person will eat 4 slices. You call the pizza place and learn t
ANEK [815]

Answer:

15 people x 4 slices so you’ll need 60 pieces

60/12(the amount of slices per pizza) =5

You need 5 pizzas. $14.78 x 5 = 73.90.

Explanation:

the answer is that one 73.90 is rounded nearest cent : ) took me a while to get it

8 0
3 years ago
Read 2 more answers
The chemical formula for beryllium oxide is BeO.A chemist determined by measurements that 0.045 moles of beryllium participated
blondinia [14]

Answer: 0.405g

Explanation:

Molar Mass of Be = 9g/mol

Number of mole of Be = 0.045mol

Mass conc. Of Be = 0.045 x 9 = 0.405g

8 0
4 years ago
How many grams of hydrogen chloride can be produced from 1.00g of hydrogen and 55.0g of chlorine? what is the limiting reactant?
zloy xaker [14]

Answer:

m_{HCl}=36.1gHCl

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the required grams of HCl by firstly identifying the limiting reactant via the moles of each reactant as they are in a 1:1 mole ratio:

n_{H_2}=1.00gH_2*\frac{1molH_2}{2.02gH_2}=0.500molH_2\\\\ n_{Cl_2}=55.0gCl_2*\frac{1molCl_2}{70.9gCl_2}=0.776molCl_2

Thus, we infer the hydrogen is the limiting reactant and therefore we use its 1:2 mole ratio with HCl whose molar mass is 36.46 g/mol:

m_{HCl}=0.500molH_2*\frac{2molHCl}{1molH_2}*\frac{36.46gHCl}{1molHCl}\\\\m_{HCl}=36.1gHCl

Regards!

4 0
3 years ago
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