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artcher [175]
3 years ago
13

Why does an orange look orange?

Chemistry
1 answer:
Evgesh-ka [11]3 years ago
4 0
I think it’s “it reflects yellow and red
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What was the name of the disease that killed nearly half the people of Europe?
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What is the final pH of a solution obtained by mixing 300 ml of 0.4 M NH3 with 175 ml of 0.3 M HCl? (Kb = 1.8 x 10-5) Show all o
MariettaO [177]

Answer:

pH of the final solution = 9.15

Explanation:

Equation of the reaction: HCl + NH₃ ----> NH₄Cl

Number of moles of  NH₃ = molarity * volume (L)

= 0.4 M * (300/1000) * 1 L =  0.12 moles

Number of moles of HCl =  molarity * volume (L)

= 0.3 M * (175/1000) * 1 L = 0.0525 moles

Since all he acid is used up in the reaction, number of moles of acid used up equals number of moles of NH₄Cl produced

Number moles of NH₄Cl produced =  0.0525 moles

Number of moles of base left unreacted =  0.12 - 0.0525 = 0.0675

pOH = pKb + log([salt]/[base])

pKb = -logKb

pOH = -log (1.8 * 10⁻⁵) + log (0.0525/0.06755)

pOh = 4.744 + 0.109

pOH = 4.853

pH = 14 - pOH

pH = 14 - 4.853

pH = 9.15

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Consider stoichiometric combustion of gasoline and air. Assume a full tank of gasoline holds 50 L (approximately 13.2 gallons),
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Answer:

520 kg

Explanation:

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C₈H₁₈(l) + 12.5 O₂(g) → 8 CO₂(g) +  9 H₂O(l)

We can establish the following relations:

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  • The molar ratio of C₈H₁₈ to O₂ is 1:12.5.
  • The mole fraction of O₂ in air is 0.21.
  • The molar mass of air is 28.96 g/mol.

50 L of isooctane require the following mass of air.

50 \times 10^{3}mLC_{8}H_{18}.\frac{0.690gC_{8}H_{18}}{1mLC_{8}H_{18}} .\frac{1molC_{8}H_{18}}{114.22gC_{8}H_{18}} .\frac{12.5molO_{2}}{1molC_{8}H_{18}} .\frac{1molAir}{0.21molO_{2}} .\frac{28.96 \times 10^{-3}kgAir}{1molAir} =520kgAir

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