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3 years ago

9

Which is the factorization of 8x^2+13-6

1 answer:

QveST [7]3 years ago

3 0

(8x+3)(x-2)

Explanation

8x^2-13x-6
X(8x+3)-2(8x+3) factor buck greatest common factor
(8x+3)(x-2)

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Ayo someome help quick i’ll give you brainliest

mojhsa [17]

Answer:

D or 4

Step-by-step explanation:

3x3.1415 is ~9.42

sq. rt. of 10 is ~3.16 so order them.

3.16 3.25 9.42 or 10, 3.25, 3pi

6 0

2 years ago

−13π/5 find the reference angle

miss Akunina [59]

I would convert to degrees first seems to make it easier.
$\frac{-13 \pi }{5}$ × $\frac{180}{ \pi }$
= -468
by adding 360 twice we get the coterminal angle 252

252 is in the 3rd quadrant so 180 is the closest angle on the x-axis
ref angle = 252 - 180 = 72

If necessary convert back to radians... $72( \frac{ \pi }{180} )= \frac{2 \pi }{5}$

8 0

3 years ago

The questions are in the images pls answer all or your answer will be deleted because this is for a lot of points and im losing

PilotLPTM [1.2K]

1)

x + 2y = 21

+ -x + 3y = 29

--------------------------

5y = 50

y = 10

x + 2(10) =21

x = 1

2)

6x + 6y = 30

+ 15x - 6y = 12

-------------------------------

21x = 42

x = 2

6(2) + 6y = 30

6y = 18

y = 3

7 0

3 years ago

What is the missing number? I’ll mark brainly

ad-work [718]

Answer:

I think it is 4

I am not sure about it

5 0

3 years ago

What is the area of this triangle ?

oee [108]

Answer:

Area of triangle is 9.88 units^2

Step-by-step explanation:

We need to find the area of triangle

Given E(5,1), F(0,4), D(0,8)

We will use formula:

$Area\,\,of\,\,triangle =\sqrt{s(s-a)(s-b)s-c)} \\where\,\, s = \frac{a+b+c}{2}$

We need to find the lengths of side DE, EF and FD

Length of side DE = a = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side DE = a = $=\sqrt{(5-0)^2+(1-8)^2}\\=\sqrt{(5)^2+(-7)^2}\\=\sqrt{25+49}\\=\sqrt{74}\\=8.60$

Length of side EF = b = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side EF = b = $=\sqrt{(0-5)^2+(4-1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\=5.8$

Length of side FD = c = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side FD = c = $=\sqrt{(0-0)^2+(8-4)^2}\\=\sqrt{(0)^2+(4)^2}\\=\sqrt{0+16}\\=\sqrt{16}\\=4$

so, a= 8.60, b= 5.8 and c = 4

s = a+b+c/2

s= 8.6+5.8+4/2

s= 9.2

Area of triangle= $=\sqrt{s(s-a)(s-b)s-c)}\\=\sqrt{9.2(9.2-8.6)(9.2-5.8)(9.2-4)}\\=\sqrt{9.2(0.6)(3.4)(5.2)}\\=\sqrt{97.5936}\\=9.88$

So, area of triangle is 9.88 units^2

4 0

3 years ago