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Sloan [31]
3 years ago
10

Which of the following are vertical asymptotes of the function y = 2cot(3x) + 4? Check all that apply. A.x = pi/3 B.x = +/- pi/2

C.x = 2pi D.x = 0
Mathematics
2 answers:
Kisachek [45]3 years ago
6 0
Vertical asymptotes occur when the denominator of a rational is 0, whilst not zeroing out the numerator, making the rational, undefined, in this case

\bf y=2cot(3x)+4\implies y=2\cdot \cfrac{cos(3x)}{sin(3x)}+4\impliedby \textit{if \underline{sin(3x)} turns to 0}\\\\
-------------------------------\\\\
\textit{let's check}
\\\\\\
A)\qquad \cfrac{cos(3x)}{sin\left( 3\frac{\pi }{3} \right)}\implies \cfrac{cos(3x)}{sin\left( \pi \right)}\implies \cfrac{cos(3x)}{0}\impliedby unde f ined

\bf B)\qquad \cfrac{cos(3x)}{sin\left( 3\frac{\pm\pi }{2} \right)}\implies\cfrac{cos(3x)}{sin\left( \frac{\pm3\pi }{2} \right)}\implies \cfrac{cos(3x)}{\pm 1}\implies \pm cos(3x)
\\\\\\
C)\qquad \cfrac{cos(3x)}{sin\left( 3(2\pi )\right)}\implies \cfrac{cos(3x)}{sin(6\pi )}\implies \cfrac{cos(3x)}{0}\impliedby unde f ined
\\\\\\
D)\qquad \cfrac{cos(3x)}{sin(3(0))}\implies \cfrac{cos(3x)}{sin(0)}\implies \cfrac{cos(3x)}{0}\impliedby unde f ined
jenyasd209 [6]3 years ago
3 0
Yeah it’s A C D for apex
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If the surface area of the box in the diagram is 204.25 square feet, what is the value of ‘x’?
Alexandra [31]

Note: Consider x be the breadth of the box.

Given:

The surface area of the box is 204.25 square feet.

Length of the box = 10 ft

Breadth of the box = x ft

Height of the box = 6.5 ft

To find:

The value of x.

Solution:

The surface area of a cuboid is:

SA=2(lb+bh+hl)

Where, l is length, b is breadth and h is height of the cuboid.

Putting SA=204.25,  l=10,\ b=x,\ h=6.5 in the above formula, we get

204.25=2(10\times x+x\times 6.5+6.5\times 10)

204.25=2(10x+6.5x+65)

204.25=2(16.5x+65)

Using distributive property, we get

204.25=2(16.5x)+2(65)

204.25=33x+130

204.25-130=33x

74.25=33x

Divide both sides by 33.

\dfrac{74.25}{33}=x

2.25=x

Therefore, the correct option is B.

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Read 2 more answers
a un baile asistieron 270 personas.si los boletos de costaban 100 pesos y los de dama 80 pesos y se recaudaron 24 800 pesos por
ser-zykov [4K]
The question in English
<span>A dance was attended by 270 people. If the gentlemen tickets cost 100 pesos and the lady tickets 80 pesos and 24800 pesos were collected for all the tickets. How many women and how many men attended the dance?

let
x---------> the number of men
y--------> the number of women

we know that
x+y=270----> x=270-y-----> equation 1
100x+80y=24800-------> equation 2
substitute equation 1 in equation 2
100*[270-y]+80y=24800----> 27000-100y+80y=24800
20y=2200-----> y=110
x=270-y----> x=270-110----> x=160

the answer is
the number of men ---> 160
the number of women----> 110

the answer in Spanish

</span>hagamos
x--------->la cantidad de hombres
y--------->la cantidad de mujeres

Sabemos que
x+y=270----> x=270-y-----> ecuacion 1
100x+80y=24800-------> ecuacion 2
sustituimos la ecuacion 1 en la ecuacion 2
100*[270-y]+80y=24800----> 27000-100y+80y=24800
20y=2200-----> y=110
x=270-y----> x=270-110----> x=160

La respuesta es
la cantidad de hombres es 160
la cantidad de mujeres es 110
4 0
3 years ago
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