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luda_lava [24]
3 years ago
15

Find the product and the quotient. 1/2 x 1/5 and 1/5 divided by 2

Mathematics
2 answers:
dimaraw [331]3 years ago
3 0

Answer:

1/2×1/5=1/10

1/5÷2=1/5×1/2=1/10

sertanlavr [38]3 years ago
3 0

Answer:

1/2 x 1/5 would be 1/10 and 1/5 divided by 2 would be 1/10

Step-by-step explanation:

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[tex]\sqrt{49} <br> please answer correctly
Nookie1986 [14]

Answer:

Um.. well I don't know what is your question, but I think you meant square root and the answer is 7 because it is a perfect square.

Step-by-step explanation:

7 0
2 years ago
Day middle school has 24 students from the 8th grade that are in band. This is 25% of all the students in 8th grade. How many st
Volgvan

Answer:

96 in 8th grade

Step-by-step explanation:

You times 24 by four to get 96. Then to check your answer you need to do 25%96 and you will get 24 to show that you are right.

6 0
3 years ago
two girls went shopping and spent $334. one girls spent $16 more thent the other girl did. how much did each spend
Taya2010 [7]

I will try my best to assist you with your question ,

First we must divide the amount by 2

334/2 = 167

Now we add 16

167 + 16=183

So, the girl spent $183

Wow, she is spoiled!

Hope I helped!

Good Luck!

3 0
3 years ago
Find the theoretical probability for rolling 6 as well as the probability for a 1
ale4655 [162]
6 is one of the six total sides on a dice. 

P(6)=1/6

1 is one of the six total sides on a dice. 

P(1)=1/6
3 0
3 years ago
PLEASE!!!!!!!The adjoining figure shows two circles with the same center. The
Nookie1986 [14]
<h3><u>Answer:</u></h3>

\boxed{\boxed{\pink{\sf \leadsto Hence \ the \ area \ of \ shaded \ region \ is 264 cm^2}}}

<h3><u>Step-by-step explanation:</u></h3>

Here , two circles are given which are concentric. The radius of larger circle is 10cm and that of smaller circle is 4cm . And we need to find thelarea of shaded region.

From the figure it's clear that the area of shaded region will be the difference of areas of two circles.

Let the,

  • Radius of smaller circle be r .
  • Radius of smaller circle be r .
  • Area of shaded region be \bf Area_{shaded}

\bf \implies Area_{Shaded}= Area_{bigger}-Area_{smaller} \\\\\bf\implies Area_{Shaded} = \pi R^2 - \pi r^2  \\\\\bf\implies Area_{shaded} = \pi ( R^2-r^2)  \\\\\bf\implies Area_{shaded} = \pi [ (10cm)^2 - (4cm)^2]  \\\\\bf\implies Area_{shaded}  = \pi [ 100cm^2-16cm^2]  \\\\\bf\implies Area_{shaded}  = \pi \times 84cm^2  \\\\\bf\implies Area_{shaded}  = \dfrac{22}{7}\times 84cm^2  \\\\\bf\implies \boxed{\red{\bf Area_{shaded} = 264 cm^2 }}

<h3><u>Hence </u><u>the</u><u> </u><u>area</u><u> </u><u>of</u><u> the</u><u> </u><u>shaded </u><u>region</u><u> is</u><u> </u><u>2</u><u>6</u><u>4</u><u> </u><u>cm²</u><u>.</u></h3>

5 0
2 years ago
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