720 miles traveled on 60
gallons of gasoline.
Express this on its Unit Rate.
To get the answer, we need to divide 720 miles by 60 gallons of gasoline
=> 720 / 60 = 12 miles /gallons
Thus, in every 1 gallon of gasoline, you can travel 12 miles.
So, the expression would be like this:
720 miles / 60 gallons = 12 miles / gallon
Let’s check our answer
=> 12 miles x 60 gallons = 720 miles.
Thus, we got the correct answer.
6 times
6 * 1/4 is 6/4
6/4 is 1 2/4 which is 1 1/2
we know that
in the right triangle of the figure
Applying the Pythagorean Theorem

therefore
the answer is the option
C) 
Using the normal distribution, it is found that 58.97% of students would be expected to score between 400 and 590.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:

The proportion of students between 400 and 590 is the <u>p-value of Z when X = 590 subtracted by the p-value of Z when X = 400</u>, hence:
X = 590:


Z = 0.76
Z = 0.76 has a p-value of 0.7764.
X = 400:


Z = -0.89
Z = -0.89 has a p-value of 0.1867.
0.7764 - 0.1867 = 0.5897 = 58.97%.
58.97% of students would be expected to score between 400 and 590.
More can be learned about the normal distribution at brainly.com/question/27643290
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No, because one x-value corresponds to two different y-values