Answer:
The number of times coin thrown was <u>500</u>.
Step-by-step explanation:
Given:
A coin lands on heads 200 times. the relative frequency of heads is 0.4.
Now, to find the times coin was thrown.
Let the number of times coin thrown was be 
Relative frequency = 0.4.
Number of lands on heads = 200.
So, to get the number of times coin was thrown we put formula:
<em>By cross multiplying we get:</em>
<em>Dividing both sides by 0.4 we get:</em>
Therefore, the number of times coin thrown was 500.
Answer:
w = (p - 21)/2
Step-by-step explanation:
Rearrange the equation so that it is equal to w.
p = 21 + 2w
p - 21 = (21 + 2w) - 21
p - 21 = 2w
(p - 21)/2 = (2w)/2
(p - 21)/2 = w
w = (p - 21)/2
I think it would be be because you’re actually saving a little bit more amount of money you’re paying a dollar and would say two cent for each bar
Answer:
D (3,1)
Step-by-step explanation:
solving simultaneous equations
Arrange equations
2x+y=7
3x-4y=5
make y side cancell by addition by multiplying by 4 and 1 as shown
4{2x+y=7}
1{3x-4y=5}
8x+4y=28
3x-4y=5
11x=33
x=33/11=3
substitute for x=3 in 3x-4y=5
9-4y=5
4=4y
y=1
Step-by-step explanation:
the diameter of a circle is simply 2×radius.
2×15.4 = 30.8 m
the diameter is 30.8 m is true.
the circumference of a circle is
2×pi×radius
2×pi×15.4 = 30.8×pi m
the circumference is 30.8pi m is true.
therefore, the circumference can be found using
2(pi)(15.4)
is true.
now, doing the pi multiplication :
30.8 × pi = 96.76105373... m
the approximate circumference is 96.7 m is true.
6 diameters would be
30.8×6 = 184.8 m
that is much longer than the circumference.
so, more than 6 diameters could be wrapped around the circle is false, if we understand it that this is supposed to wrap the circle once without any overhanging remainder.
