When
NaC2H3O2 is in solution, it would act as a base since it ionizes into sodium
ions and acetate ions, the acetate ions would interact with water with the
following reaction:<span>
C2H3O2- + H2O <---> C2H3O2H + OH-
So, from the reaction, hydroxide ions are formed
giving it basic properties. We calculate as follows:
[NaC2H3O2] = [Na+] = [C2H3O2-] = 0.250 m
By the ICE table:
[C2H3O2-] C2H3O2H OH-
I
0.250
0 0
C
-x
+x +x
------------------------------------------------------------
E 0.250
- x x
x
1.80×10^−5 = x^2 / (0.250 - x)</span>
Solving for x, we have
x = 0.002112
pOH = -log 0.002112
pOH = 2.68
pH = 14 - 2.68 = 11.32
Therefore, the pH of the solution is about 11.32.
You can look on the periodic table for the number of automic mass units in each element.
1 mole Li = 6.94 amu
6.94 • 2 = 13.9 amu
There are 13.9 amu in 2 moles of Li
Answer:
the partial of colloidal are smaller and they are not heavy whereas the partial of suspension are larger but they are heavy and less movement thus they settle down due to gravity
All four answers are right 100%.
