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irakobra [83]
4 years ago
8

Which statement explains why carbon dioxide (CO2) is a gas at room temperature? A. There are constant interactions between the C

O2 molecules. B. There are weak interactions between the CO2 molecules. C. There are no interactions between the CO2 molecules. D. There are strong interactions between the CO2 molecules.
Chemistry
1 answer:
Nezavi [6.7K]4 years ago
6 0

Answer:

B) There are weak interactions between the CO2 molecules.

Explanation:

Carbon dioxide is composed of one carbon atom that is structured between two atoms of oxygen, they are bonded with double bond and the CO2 is symmetrical because of the arrangement of the bond between them.It is less electronegative than Oxgen, this gives Oxgen the ability to attract the electron to themselves, and there is no intermolecular existing within carbon dioxide other bands waal forces.Compounds that are gases under the condition of room temperatures, and pressure usually have have small molecules. and their molecules is usually have van der Waals forces acting between them and theses forces are weak.This allows carbon dioxide molecules to be able to move freely as a gas.

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Which has a larger electronegativity O or F?
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3 years ago
A beaker of water has a volume of 125mL and a density of 1.0g/mL. Calculate the mass of the water.​
Butoxors [25]

Answer:

125 g

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6 0
3 years ago
Consider the nuclear equation below. Superscript 235 subscript 92 upper U right arrow superscript 4 subscript 2 upper H e. What
coldgirl [10]

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\rm_{90}^{231}\text{Th}

Explanation:

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\rm _{92}^{235}\text{U} \longrightarrow \,  _{2}^{4}\text{He} + X

Let's write X as a nuclear symbol.

\rm _{92}^{235}\text{U} \longrightarrow \,  _{2}^{4}\text{He} + _{Z}^{A}\text{X}

The main point to remember in balancing nuclear equations is that the sums of the superscripts and of the subscripts must be the same on each side of the reaction arrow.

Then

235 = 4 + A , so A = 235 - 4 = 231, and

 92 = 2 + Z , so  Z =   92 - 2 =  90

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\rm _{92}^{235}\text{U} \longrightarrow \,  _{2}^{4}\text{He} +\, _{90}^{231}\text{X}

Element 90 is thorium, so  

\rm X = _{90}^{231}\text{Th}

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4 years ago
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