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3 years ago

How to write 103,727,495 in expanded form

Mathematics

2 answers:

hram777 [196]3 years ago

7 0

The expanded form is
100,000,000+3,000,000+700,000+20,000+7,000+400+90+5

ArbitrLikvidat [17]3 years ago

5 0

The answer is 100,000,000+3,000,000+700,000+20,000+7,000+400+90+5.

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Ned rides his bike 6 miles to the store and 6 miles back. The graph shows the relationship between the distance Ned is from home

Degger [83]

Answer:

The answer is D

Step-by-step explanation:

A cant be right because the graph isn't a straight line.

B cant be right because from 0 to 60 the graph the line goes at a(n) upward slope not a straight line.

Although the first part of question c is right, the second part is wrong. From 50-90 the ling goes at a downward slope via decreasing, which isn't equal like it said so question C is wrong.

So the correct answer is D

3 0

2 years ago

Simplify. (√5+4) (√5 - 2)

son4ous [18]

Answer:

2√5 - 3

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Algebra I</u>

Terms/Coefficients
Expand by FOIL

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

(√5 + 4)(√5 - 2)

<u>Step 2: Simplify</u>

Expand [FOIL]: (√5)² - 2√5 + 4√5 - 8
Combine like terms: (√5)² + 2√5 - 8
Evaluate exponents: 5 + 2√5 - 8
Combine like terms: 2√5 - 3

6 0

3 years ago

Read 2 more answers

Ken, a single taxpayer, has a gross income of $79,685. He claims one exemption and can take a deduction of $1,257 for medical ex

Ganezh [65]

The answer is c. $12,675 just took the test

4 0

4 years ago

Read 2 more answers

The average daily temperature, t, in degrees fahrenheit for a city as a function of the month of the year, m, can be modeled by

Vikentia [17]

The answer will be t = $sin((m.\frac{\pi}{6})+55)$ average daily temperature, t, in degrees Fahrenheit for a city as a function of the month of the year.

<h3>What is temperature?</h3>

Temperature is the degree or intensity of heat present in a substance or object, especially as expressed according to a comparative scale and shown by a thermometer or perceived by touch.

<h3>TO SOLVE:</h3>

$35cos(\frac{\pi}{6(m+3)}+55)\\\\35 cos(\frac{\pi m}{6} + 55 + \frac{\pi}{2})\\$

suppose $x = m.\frac{\pi}{6}+55$ and $\frac{\pi}{2} = 90$ degree

We know, cos(x+90°) = - sin(X)

⇒ $cos((m.\frac{\pi}{6})+55+90degree)$ degree = - $sin((m.\frac{\pi}{6})+55)$

⇒ t = $sin((m.\frac{\pi}{6})+55)$

Hence the answer will be t = $sin((m.\frac{\pi}{6})+55)$ average daily temperature, t, in degrees Fahrenheit for a city as a function of the month of the year.

To learn more visit:

brainly.com/question/27441712

#SPJ4

3 0

2 years ago

48 is 32% of what number?

Irina18 [472]

Answer:

150

Step-by-step explanation:

Because I looked it up

4 0

3 years ago