Associative,commutative and distributive
Answer:
Equations:
--- Cindy
--- Ruben
Solution to equation:
Time they have the same amount: 14 minutes
Number of cards they have at that time: 140 flashcards
Step-by-step explanation:
Solving (a): Variables and what they represent
The variables to use are x and y
Where x represent the minutes and y represents the number of flashcards in x minutes
Solving (b): System of linear equation
Cindy:
per minute
Total number of flashcards (y) in x minutes is:
Ruben:
per minute
Total number of flashcards (y) in x minutes is:
Solution to Equations:
Time they have the same amount.
To do this, we expressions
i.e.
Collect Like Terms
Number of cards they have at that time.
Here, we simply substitute 14 for x in any of the equations.
or
9 1/2 = 19/2
(29/5) / (19/2)
When changing division to multiplication, flip the number (right hand side).
(29/5) * (2/19)
58/95
Answer: 120 ways
Step-by-step explanation: In this problem, we're asked how many ways can 5 people be arranged in a line.
Let's start by drawing 5 blanks to represent the 5 different positions in the line.
Now, we know that 5 different people can fill the spot in the first position. However, once the first position is filled, only 4 people can fill the second spot and once the second spot is filled, only 3 people can fill the third spot and so on. So we have <u>5</u> <u>4</u> <u>3</u> <u>2</u> <u>1</u>.
Now, based on the counting principle, there are 5 x 4 x 3 x 2 x 1 ways for all 5 spots to be filled.
5 x 4 is 20, 20 x 3 is 60, 60 x 2 is 120, and 120 x 1 is 120.
So there are 120 ways for all 5 spots to be filled which means that there are 120 ways that 5 people can be arranged in a line.
I have also shown my work on the whiteboard in the image attached.