Every difference of squares problem can be factored as follows: a2 – b2 = (a + b)(a – b) or (a – b)(a + b). So, all you need to do to factor these types of problems is to determine what numbers squares will produce the desired results. Step 3: Determine if the remaining factors can be factored any further.
The length is 14
Just count the spaces in between to get the result of 14
so it says 6 times as old as June
so that would be 6x
then it said the sum so that's addition is no less than so that's subtraction
so it would be
X because we June's father age
so x times 6 > 77
3 sin x = 2 ( 1 - sin² x )
3 sin x = 2 - 2 sin² x
2 sin² x + 3 sin x - 2 = 0
Substitution: t = sin x
2 t² + 3 t - 2 = 0
t 1/2 =

t 1 = 1/2
t 2 = - 2 ( this solution is not acceptable )
sin x = 1/2
Answer:
x 1 = π / 6 + 2 kπ, x 2 = 5 π / 6 + 2 k π, k ∈ Z