Answer:
The mass of NaHCO3 required is 235.22 g
Explanation:
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Continuation of Question:
2NaHCO3(s) + H2SO4(aq) → Na2SO4(aq) + 2CO2(g) + 2H2O(l)
You estimate that your acid spill contains about 1.4 mol H2SO4. What mass of NaHCO3 do you need to neutralize the acid?
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The question requires us to calculate the mass of NaHCO3 to neutralize the acid.
From the balanced chemical equation;
1 mol of H2SO4 requires 2 mol of NaHCO3
1.4 would require x?
Upon solving for x we have;
x = 1.4 * 2 = 2.8 mol of NaHCO3
The relationship between mass and number of moles is given as;
Mass = Number of moles * Molar mass
Mass = 2.8 mol * 84.007 g/mol
Mass = 235.22 g
The answer is activation energy. This is the minimum amount of energy needed to start a reaction. This is introduced by Svante Arrhenius. Also, it is the maximum amount of energy required. Activation energy can also be thought of the energy barrier.
<span>In oxido-reduction
reaction, at least one element lose and one element gain electrons.</span>
Oxidation
reaction is increasing of oxidation number of atom, because element lost electrons in chemical reaction.
Reduction is lowering
oxidation number because atom gain electrons.
For example, in oxidation-reduction reaction: 2H₂ + O₂ → 2H₂O; hydrogen is oxidized (change oxidation number from 0 to +1) and oxygen i s reduced (change oxidation number from 0 to -2).
Answer:
Ne with eight dots
Explanation:
On the periodic table, Neon is in group 8A. The group can be used to determine the number of valence electrons.
The dots in the Lewis structure diagram represent the number of valence electrons.