Which of the following is the correct Lewis structure diagram for Neon? The letters Ne with eight dots The letters Ne with seven
dots The letters Ne with six dots The letters Ne with five dots
2 answers:
Answer : The correct option is, The letters Ne with eight dots.
Explanation :
Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.
In the Lewis-dot structure the valance electrons are shown by 'dot'.
The representation of valence electrons of an atom by dots around the symbol of an element is said to be the Lewis-dot symbol.
In the representation of Lewis-symbol, one electron dot must put on each side of the element symbol then paired the electrons.
The given atom is, neon (Ne)
The electronic configuration of neon atom is,
As we know that neon has '8' valence electrons.
The Lewis-dot structure of neon atom is shown below.
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Answer : The voltage of the voltaic cell is 1.14 V
Explanation :
From the given cell representation, we conclude that
The copper will undergo reduction reaction will get reduced. Zinc will undergo oxidation reaction and will get oxidized.
The oxidation-reduction half cell reaction will be,
Oxidation half reaction:
Reduction half reaction:
Oxidation reaction occurs at anode and reduction reaction occurs at cathode. That means, gold shows reduction and occurs at cathode and chromium shows oxidation and occurs at anode.
The overall balanced equation of the cell is,
To calculate the of the reaction, we use the equation:
Putting values in above equation, we get:
Now we have to calculate the emf or voltage of the cell.
Using Nernest equation at 298 K :
where,
n = number of electrons in oxidation-reduction reaction = 2
= ?
Now put all the given values in the above equation, we get:
Therefore, the voltage of the voltaic cell is 1.14 V