Answer:
64.4
Step-by-step explanation:
In one of the trig formulas, it states sin <a/A = sin<b/B = sin<c/C
So we have in this case:
sin(70)/12 = sin x/14 Note: x is just a variable for the angle <ABC
14(sin70)/12 = sin x
sin^-1(14(sin70)/12) = x
x=64.4
Your welcome, and comment if you have any questions! :D
What is the third quartile of the data set? 23, 35, 55, 61, 64, 67, 68, 71, 75, 94, 99
lara [203]
Answer:
75
Step-by-step explanation:
Q1=55 Q2=67 Q3=75
The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.
Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>
We calculate the cross product as a determinant of (i,j,k) and the normal products
i j k
5 -1 -6
1 1 1
=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>
Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0
Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
The answer is (3p-5pt)/12
remove parenthesis but the terms are connected.
Answer:
Step-by-step explanation:
