Question

A 30 cm-long wire carrying a current of 0.5 A is immersed in a uniform magnetic field of 4 T. If the magnetic field is oriented perpendicular to the wire, what is the magnitude of the force that the wire will experience?

Answer 1

Answer:

Magnetic force, F = 0.6 N

Explanation:

It is given that,

Length of the wire, L = 30 cm = 0.3 m

Current carrying in the wire, I = 0.5 A

Uniform magnetic field, B = 4 T

To find,

The magnetic force

Solve,

A force is exerted by the wire in the magnetic field that is given by :

$F=ILB\ sin\theta$

Here, $\theta=90$

$F=ILB$

$F=0.5\ A\times 0.3\ m\times 4\ T$

F = 0.6 N

Therefore, the magnetic force exerted by the wire in the magnetic field is 0.6 N