Answer:
The current through the tube is 73.39A.
Explanation:
The relationship between the resistivity , the electric field , and the current density is given by
This equation can be solved for to get:
Since the current is
Now, for the tube of mercury , , and the area is ; therefore,
Hence, the current through the mercury tube is 73.39A.
PE = mgh₁ - mgh₂= 12.5J
h₁ = ?
h₂ = 0
h₁ = PE / mg = 12.5 / 9.8
Answer:
36.408cm3
Explanation:
Since we acknowledge that density is d= m/v, once we switch it up to maintain v as the number to be found it will change to v=m/d. Therefore, 275.32/7.562 is 36.408 and the unit is cm cube!
Hope that helped!!
Answer:
2.5 cm
Explanation:
Using the relation :
Refractive index = Real Depth / Apparent depth
Refractive index = 1.6
Real depth = 4cm
Virtual depth = apparent depth = x
1.6 = 4cm / x
1.6x = 4
x = 4 / 1.6
x = 2.5
Hence, virtual depth = 2.5cm