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Nata [24]
2 years ago
14

Inside a car that was at 273 K, a bottle with a pressure at 100,000 pascals warms up to

Physics
1 answer:
Deffense [45]2 years ago
5 0

Answer:

P2 = 128,205 pascal.

Explanation:

<u>Given the following data;</u>

Original Pressure, P1 = 100,000 pascals

Original Temperature, T1 = 273K

New Temperature, T2 = 350K

To find new pressure P2, we would use Gay Lussac' law.

<em>Gay Lussac's law states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas. </em>

Mathematically, Gay Lussac's law is given by;

PT = K

Where;

  • P represents pressure.
  • T represents temperature.
  • K is the constant of proportionality.

\frac{P1}{T1} = \frac{P2}{T2}

<em>Making P2 as the subject formula, we have;</em>

P_{2}= \frac{P1}{T1} * T_{2}

Substituting into the equation, we have;

P_{2}= \frac{100000}{273} * 350

P_{2}= 366.3004* 350

P2 = 128205.13 ≈ 128205 pascal.

<em>Therefore, the pressure inside the hot water bottle is 128,205 pascal. </em>

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