Inside a car that was at 273 K, a bottle with a pressure at 100,000 pascals warms up to
1 answer:
Answer:
P2 = 128,205 pascal.
Explanation:
<u>Given the following data;</u>
Original Pressure, P1 = 100,000 pascals
Original Temperature, T1 = 273K
New Temperature, T2 = 350K
To find new pressure P2, we would use Gay Lussac' law.
<em>Gay Lussac's law states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas. </em>
Mathematically, Gay Lussac's law is given by;
Where;
- P represents pressure.
- T represents temperature.
- K is the constant of proportionality.
<em>Making P2 as the subject formula, we have;</em>
Substituting into the equation, we have;
P2 = 128205.13 ≈ 128205 pascal.
<em>Therefore, the pressure inside the hot water bottle is 128,205 pascal. </em>
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Answer:
Because there is no air resistance
Explanation:
When an object falls on Earth, there are essentially two forces acting on it:
- The force of gravity, downward, equal to the weight of the object:
where m is the mass and g the acceleration due to gravity
- The air resistance, F, which acts upward, and whose magnitude is generally proportional to v, the speed of the object
When the object starts its fall, its initial speed is zero: v = 0, so the air resistance is also zero: F=0, and the object accelerates downward due to gravity.
However, as it accelerates downward, its speed increases, and so does the air resistance F. However, F is upward, opposite to the direction of motion, therefore it reduces the net acceleration of the object; at a certain point, the magnitude of the air resistance will become equal to the weight, so that
mg = F
and at that point, the net acceleration of the object will become zero: this means that the object will continue its fall at a constant velocity, called terminal velocity.
On the Moon instead, there is no air resistance: this means that for an object falling down, the speed keeps increasing due to the effect of gravity, and it will never reach a terminal value: therefore, the final velocity at the impact will be much higher than on the Earth, if we assume the two objects have been dropped from a very high altitude from the surface.