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Dimas [21]
3 years ago
7

A sound wave with a frequency of 300 hertz is traveling a medium at a speed of 320 meters/second. What is it’s wavelength

Physics
2 answers:
user100 [1]3 years ago
8 0
Wavelength = (speed) / (frequency)

Wavelength = (320 m/s) / (300 / sec)

Wavelength = (1 and 1/15) m/s
erik [133]3 years ago
8 0

Answer:

1.07m

Explanation:

Wavelength of a wave is the distance between two successive crest and trough of a wave. It can be expressed as the ratio of the speed of the wave (v) to its frequency (f)freq 300

Mathematically,

wavelength (¶) = speed of wave (v)/frequency (f)

Given speed = 320m/s and frequency = 300Hertz

Wavelength = 320/300

Wavelength = 1.07m

The wavelength of the wave is therefore 1.07m

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In an effort to decrease the mAs of an exposure, the 15% rule of kVp change may be considered. Changing the original kVp of 84 u
Roman55 [17]

Answer:

Will result in :Greater Compton scatter interaction

Explanation

This is because The 15% rule states that changing the kVp by 15% has the same effect as doubling the mAs, or reducing the mAs by 50%; that is A 15% increase in kVp has the same effect as doubling the mAs and vice versa but in this case reducing mas causes more Compton scatter because Compton scattering occurs at a lower kvp

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3 years ago
What is the equivalent of 0° C in Kelvin?<br> Help will give brainiest
givi [52]

Answer:

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Why does the earth bulge at the equator?
sattari [20]

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4 0
3 years ago
5.54 Two kilograms of air within a piston–cylinder assembly WP execute a Carnot power cycle with maximum and minimum temper atur
Step2247 [10]

Answer:

A) 60%

B) p2 = 1237.2 kPa

   v2 = 0.348 m^3

C) w1-2 = w3-4 = 1615.5 kJ

   Q2-3 = 60 kJ

Explanation:

A) calculate thermal efficiency

  Л = 1 - \frac{Tl}{Th}  

where Tl = 300 k

            Th = 750 k

hence thermal efficiency ( Л ) = [1 - ( 300 / 750 )] * 100 = 60%

B) calculate the pressure and volume at the beginning of the isothermal expansion

calculate pressure ( P2 )  :

= P3v3 = mRT3  ----- (1)

v3 = 0.4m , mR = 2* 0.287, T3 = 750

hence P3 = 1076.25

next equation to determine P2

Qex = p3v3 ln( p2/p3 )

60 = 1076.25 * 0.4 ln(p2/p3)

hence ; P2 = 1237.2 kpa

calculate volume ( V2 )

p2v2 = p3v3

v2 = p3v3 / p2

   = (1076.25 * 0.4 ) /  1237.2  

  = 0.348 m^3

C) calculate the work and heat transfer for each four processes

work :

W1-2 = mCv( T2 - T1 )

        = 2*0.718 ( 750 - 300 ) = 1615.5 kJ

W3-4 = 1615.5 kJ

heat transfer

Q2-3 = W2-3 = 60KJ

Q3-4 = 0

D ) sketch of the cycle on p-V coordinates

attached below  

6 0
3 years ago
Consider this situation: A baseball player dives head-first
siniylev [52]
Of the forces listed I think the force of him diving and sliding across the infield acted on the player.

I think so because the slowing down was a result of an action, and I don’t think that should count as An action when it is the result of an action. However, the act of diving head-first into second base and sliding across the infield are independent actions and will cause friction, which will act upon the player.
7 0
3 years ago
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