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4 years ago

6

The buoyant force works opposite of: 1.weight 2. acceleration 3. mass

1 answer:

aalyn [17]4 years ago

8 0

The answer to question is number 1.weight

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What was the name of charles lindbergh’s single winged airplane for his solo flight across the atlantic?

aev [14]

Answer:

Spirit of St. Louis

Explanation:

Charles Lindbergh was known as a prolific aviator during the early twentieth century. He is well known for the flight he took from Long Island, New York, to Paris, France. It was a continuous flight across the Atlantic Ocean.

The plane he used was the Spirit of St. Louis which took more than 33 hours to complete the journey. It was the first successful flight of this kind. The airplane flew from Long Island on May 20 and landed in Paris on May 21.

4 0

4 years ago

An eagle is flying horizontally at a speed of 2.60 m/s when the fish in her talons wiggles loose and falls into the lake 4.60 m

sergij07 [2.7K]

Answer:

9.495 m/s

Explanation:

initial horizontal speed, ux = 2.60 m/s

initial vertical speed, uy = 0

height, h = 4.60 m

acceleration due to gravity, g = 9.8 m/s^2

Let the speed of fish is v as it hits the water level.

Use third equation of motion in vertical direction

$v^{2}= u^{2}+2as$

$v^{2}= 0^{2}+2\times 9.8\times 4.60$

v = 9.495 m/s

Thus, the fish hits the water level with the speed of 9.495 m/s.

8 0

3 years ago

19.A 20 kg sign is pulled by a horizontal force such that the single rope (originally vertical) holding the sign makes an angle

Andreyy89

Answer:

A) $T=209.94N$

B) $F=75.24N$

Explanation:

Using the free body diagram and according to Newton's first law, we have:

$\sum F_y=Tcos(21^\circ)-mg=0(1)\\\sum F_x=F-Tsin(21^\circ)=0(2)$

A) Solving (1) for T:

$T=\frac{mg}{cos(21^\circ)}\\T=\frac{20kg(9.8\frac{m}{s^2})}{cos(21^\circ)}\\T=209.94N$

B) Solving (2) for F:

$F=Tsin(21^\circ)\\F=(209.94N)sin(21^\circ)\\F=75.24N$

8 0

3 years ago

An explorer in Antarctica leaves his shelter during a whiteout. He takes 40 steps northeast, next 80 steps at 60o north of west,

Anvisha [2.4K]

Answer:

i need free pints rq

Explanation:

4 0

4 years ago

In a heat engine if 1000 j of heat enters the system the piston does 500 j of work, what is the final internal energy of the sys

son4ous [18]

Answer:

2500 J

Explanation:

We can solve the problem by using the first law of thermodynamics:

$\Delta U =U_f - U_i =Q-W$

where

Uf is the final internal energy of the system

Ui is the initial internal energy

Q is the heat added to the system

W is the work done by the system

In this problem, we have:

Q = +1000 J (heat that enters the system)

W = +500 J (work done by the system)

Ui = 2000 J (initial internal energy)

Using these numbers, we can re-arrange the equation to calculate the final internal energy:

$U_f = U_i + Q-W=2000 J+1000 J-500 J=2500 J$

3 0

4 years ago