Given the Arithmetic series A1+A2+A3+A4 11+15+19+23+...+71 what is the value of sum?
2 answers:
first off, let's notice the arithmetic sequence is moving as
so is adding "4" to the current term in order to get the next term, meaning the "common difference" of d = 4, and the first term is of course 11.
so, hmmm what ordinal value is the last number of 71 anyway?
low and behold, so 71 is the 16th term, well, let's get their sum then.
656 is the final answer :)
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