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3 years ago

A. A parabola opening upward, shifted 8 units right, and 5 units down.

Mathematics

1 answer:

Lesechka [4]3 years ago

5 0

Answer:

A) y=(x-8)^2-5

B)y=10(x+6)^2

C) y=-0.6(x+7)^2-2

Step-by-step explanation:

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A gem cutter cuts a polyhedral crystal from a garnet gemstone. The crystal has 10 fewer vertices than edges and twice as many ed

Vikki [24]

Answer:

vertices (V) = 6, faces (F) = 12 and edges (E) = 16

Step-by-step explanation:

A polyhedron is a three-dimensional shape with straight edges and flat faces and sharp corners.The point where the faces of a polyhedron meet each other is known as the edge while the corners of the polyhedron is known as the vertices.

Euler formula gives the relationship between the number of vertices (V), faces (F) and edges (E) of a polyhedron. This formula is given as:

F + V - E = 2.

Given that:

E - V = 10, Therefore E = V + 10

F = 2 × V = 2V

Substituting into the Euler formula:

2V + V - (V + 10) = 2

2V + V - 10 - V = 2

2V = 12

V = 12/2 = 6

Therefore, E = V + 10 = 6 + 10 = 16

F = 2V = 2 × 6 = 12

3 0

4 years ago

Use stoke's theorem to evaluate∬m(∇×f)⋅ds where m is the hemisphere x^2+y^2+z^2=9, x≥0, with the normal in the direction of the

ludmilkaskok [199]

By Stokes' theorem,

$\displaystyle\int_{\partial\mathcal M}\mathbf f\cdot\mathrm d\mathbf r=\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S$

where $\mathcal C$ is the circular boundary of the hemisphere $\mathcal M$ in the $y$ - $z$ plane. We can parameterize the boundary via the "standard" choice of polar coordinates, setting

$\mathbf r(t)=\langle 0,3\cos t,3\sin t\rangle$

where $0\le t\le2\pi$ . Then the line integral is

$\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=\int_{t=0}^{t=2\pi}\mathbf f(x(t),y(t),z(t))\cdot\dfrac{\mathrm d}{\mathrm dt}\langle x(t),y(t),z(t)\rangle\,\mathrm dt$
$=\displaystyle\int_0^{2\pi}\langle0,0,3\cos t\rangle\cdot\langle0,-3\sin t,3\cos t\rangle\,\mathrm dt=9\int_0^{2\pi}\cos^2t\,\mathrm dt=9\pi$

We can check this result by evaluating the equivalent surface integral. We have

$\nabla\times\mathbf f=\langle1,0,0\rangle$

and we can parameterize $\mathcal M$ by

$\mathbf s(u,v)=\langle3\cos v,3\cos u\sin v,3\sin u\sin v\rangle$

so that

$\mathrm d\mathbf S=(\mathbf s_v\times\mathbf s_u)\,\mathrm du\,\mathrm dv=\langle9\cos v\sin v,9\cos u\sin^2v,9\sin u\sin^2v\rangle\,\mathrm du\,\mathrm dv$

where $0\le v\le\dfrac\pi2$ and $0\le u\le2\pi$ . Then,

$\displaystyle\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S=\int_{v=0}^{v=\pi/2}\int_{u=0}^{u=2\pi}9\cos v\sin v\,\mathrm du\,\mathrm dv=9\pi$

as expected.

7 0

3 years ago

47, 47, 26, 73, 61<br><br> What is the mean?

77julia77 [94]

Answer:

mean =47+47+26+73+61 / 5

= 254/5

= 50.8

4 0

3 years ago

Read 2 more answers

Plsssssssssssssssssss<br> Am asking someone really really need it.

Serjik [45]

Try Photomath; to see if it helps

7 0

3 years ago

Pls answer this question I give brainliest thank you!

matrenka [14]

Answer:

(0-10)

Step-by-step explanation:

If she plans to use 10 intervals and the highest number in the data set is just under 100, then it makes sense to split the histogram into ten intervals of 10.

6 0

3 years ago