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Solnce55 [7]
3 years ago
15

A doctor has an annual income of $152,125. The income tax the doctor has to pay is 6% , what is the amount of income tax in doll

ars and cents that the doctor has to pay ?
( this is a griddable question by the way )
Mathematics
2 answers:
kupik [55]3 years ago
5 0
I believe the amount of income tax the doctor has to pay is $9,127.5
Scilla [17]3 years ago
5 0

Answer:

<em>The amount of income tax is $9127.50  or  912750 cents.</em>

<em></em>

Step-by-step explanation:

Amount of annual income = \$152,125

Rate of income tax = 6\%

So, the amount of income tax in dollars

= 6\% of \$152,125

=(\frac{6}{100}\times \$152125 )= \$9,127.50

and in cents =(9127.50\times 100) cents = 912750cents

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6th grade math help me pleaseee
creativ13 [48]

Answer:

B and D

Step-by-step explanation:

First off, we can rotate it. When rotating, I found that the x and y values switch places in a way.

We would need to rotate it 90 degrees counterclockwise about the origin in order to get it in the same position as triangle BDE. This makes statement B correct.

In order to make triangle ABC smaller, the dilation would have to be smaller than one. Counting the right side's length, ABC has 6 squares and BDE has 3.

This would mean 6 * 1/2 = 3, meaning statement D is true.

6 0
3 years ago
Read 2 more answers
For the function f(x) = x + 9, find (f o f-1)(5) A. 14 B. 5 C. -5 D. 25
Alex Ar [27]
F-1:
y=x+9
y-9=x
x-9=f-1
f-1(14)=14-9=5 f-1(5)=5-9=-4  f-1(-5)=-5-9=-14 f-1(25)=25-9=16
f(14)=14+9=24 f(5)=5+9=14 f(-5)=9-5=4 f(25)=25+9=34
5 0
3 years ago
What is the mean weight ___ pounds ?
natulia [17]
It is 84 ibs
Explanation
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8 0
3 years ago
The quantity is called the pooled variance estimate of the common variance of two unknown but equal population variances. It is
lozanna [386]

Answer:

sample variances

Step-by-step explanation:

The pooled variance method is used to estimate the variance of several different population with different means, but are assume to have the same variance.

The weights represent the sample variances.

So the correct answer is

sample variances

5 0
3 years ago
Factoring Trinomials
alexandr402 [8]
25 a² + 20 ab +  4 b²

for formula a^x+bx^ky^k+cy ^{2k } find  u,v such that: u.v = a

and u+v = b  then  group according to (ax ^{2k} +ux^ky^k)+(vx^ky^k+cy ^{2k} )

= (25a^2+10ab)+(10ab+4b^2)

factor out 5a from : 25a^2+10ab : 5a(2b+5a)

factor out 2b from : 10ab+4b^2: 2b(2b+5a)

= 5a(2b+5a) + 2b(2b+5a)

factor out : (5a+2b)

= (5a+2b)(5a+2b)

Refine:

(2b+5a)^2

hope this helps!.


3 0
4 years ago
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