<u>Answer:</u> The molality of solution is 0.782 m
<u>Explanation:</u>
Molality is defined as the amount of solute expressed in the number of moles present per kilogram of solvent. The units of molarity are mol/kg. The formula used to calculate molality:
.....(1)
Given values:
Moles of = 0.395 mol
Mass of solvent (water) = 0.505 kg
Putting values in equation 1, we get:
Hence, the molality of solution is 0.782 m
Answer:
a. Moles of = 0.001643 moles
b. 0.296 g
c. 0.3098 g
d. Not acceptable
Explanation:
a.
Considering:
Or,
Given :
For :
Molarity = 0.1052 M
Volume = 15.62 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 15.62×10⁻³ L
Thus, moles of :
Moles of = 0.001643 moles
b.
The reaction of NaOH with the acetylsalicylic acid is in the ratio of 1:1.
Thus, Moles of NaOH = Moles of acetylsalicylic acid = 0.001643 moles
Molar mass of acetylsalicylic acid = 180.16 g/mol
The formula for the calculation of moles is shown below:
Thus,
Mass = Moles * Molar mass = 0.001643 moles * 180.16 g/mol = 0.296 g
c.
1.159 g of sample contains 0.296 g of acetylsalicylic acid
1.213 g of sample contains g of acetylsalicylic acid
Mass of acetylsalicylic acid = 0.3098 g = 309.8 mg
d. Sample contains = 309.8 mg
Manufacturer claiming = 315 mg to 335 mg
Thus , it is not acceptable.