The ball will accelerate at a rate of ![3.11 m/s^2](https://tex.z-dn.net/?f=3.11%20m%2Fs%5E2)
Explanation:
We can describe the motion of the ball by using Newton's second law, which states that the net force exerted on an object is equal to the product between the mass of the object and its acceleration:
![F=ma](https://tex.z-dn.net/?f=F%3Dma)
where
F is the net force
m is the mass
a is the acceleration
In this problem,
F = 14 N is the force exerted on the ball
m = 4.5 kg is the mass of the ball
Solving the equation, we find its acceleration:
![a=\frac{F}{m}=\frac{14}{4.5}=3.11 m/s^2](https://tex.z-dn.net/?f=a%3D%5Cfrac%7BF%7D%7Bm%7D%3D%5Cfrac%7B14%7D%7B4.5%7D%3D3.11%20m%2Fs%5E2)
So, the ball will accelerate at a rate of
.
Learn more about Newton's second law:
brainly.com/question/3820012
#LearnwithBrainly
Answer:
500N/m
Explanation:
Original Length = 20cm
Final length = 22cm
extension = 22 - 20 = 2cm = 0.02m
Force F = 10N
From Hooke's law, F = ke
==> k = F/e = 10/0.02 = 500N/m
Answer:
![\omega_1=150rads/sec](https://tex.z-dn.net/?f=%5Comega_1%3D150rads%2Fsec)
Explanation:
From the question we are told that:
Number of Revolution ![N=15=30\pi](https://tex.z-dn.net/?f=N%3D15%3D30%5Cpi)
Deceleration ![d= -120 rads/2](https://tex.z-dn.net/?f=d%3D%20-120%20rads%2F2)
Generally the equation for initial angular speed
is mathematically given by
![\omega_2^2=\omega_1^2 +2(d)(N)](https://tex.z-dn.net/?f=%5Comega_2%5E2%3D%5Comega_1%5E2%20%2B2%28d%29%28N%29)
![0=\omega_1^2 +2(-120)(20 \pi)](https://tex.z-dn.net/?f=0%3D%5Comega_1%5E2%20%2B2%28-120%29%2820%20%5Cpi%29)
![\omega_1^2=7200 \pi](https://tex.z-dn.net/?f=%5Comega_1%5E2%3D7200%20%5Cpi)
![\omega_1=150rads/sec](https://tex.z-dn.net/?f=%5Comega_1%3D150rads%2Fsec)
when you do positive work on an object, you ______
A. decrease the object's energy
<u>B. keep the object's energy the same
</u>
C. increase the object's energy
D. may increase or decrease the object's energy
It's i<span>onic Compunds hope it helps!</span>