Answer:
1) t ≈ 14.985 seconds
2) The maximum height reached ≈ 1101.4 meters
3) The velocity with which it hits the ground = 147 m/s
4) The total time in the air ≈ 29.969 seconds
Explanation:
1) The given information are;
The initial velocity of the mortar shell = 147 m/s
The direction of the mortar shell = Vertically upwards
Therefore, we have, from the equation of motion
v = u - g·t
Where;
v = The final velocity = 0 at maximum height
u = The initial velocity = 147 m/s
g = The acceleration due to gravity = 9.81 m/s²
Therefore, we have;
0 = 147 - 9.81 × t
9.81 × t = 147
t = 147/9.81 ≈ 14.985 seconds
t ≈ 14.985 seconds
2) From the equation of motion, v² = u² - 2×g×s
Where;
s = The maximum height reached
We have;
0² = 147² - 2×9.81×s
2×9.81×s = 147²
s = 147²/(2×9.81) ≈ 1101.4 meters
The maximum height reached ≈ 1101.4 meters
3) The velocity with which it hits the ground is equal to the initial velocity = 147 m/s
4) The total time in the air = 2 × The time it takes to reach maximum height
The total time in the air = 2 × 14.985 ≈ 29.969 seconds
The total time in the air ≈ 29.969 seconds
