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2 years ago

Addition of _____________ to pure water causes the greatest increase in conductivity.

Physics

2 answers:

postnew [5]2 years ago

6 0

It's i<span>onic Compunds hope it helps!</span>

Artyom0805 [142]2 years ago

4 0

Salt because if its pure water its fresh water and when salt is added to fresh water it turns into salt water witch is more likely to boil first and burn first. hope this helps

You might be interested in

Which measurement is equivalent to 350 milliliters?

tensa zangetsu [6.8K]

350 milliliters equals to .35 liters
Therefore, 3.5 times 10^-1 would be the only correct answer since that is the only one that matches .35 liters

4 0

2 years ago

The density of air is 1.3 kg/m^3. What mass of air is contained in a room measuring 2.5m x 4m x 10m? Give your answer in kg. Bra

krek1111 [17]

Mass= density x volume
1.3 kg/m^3 x ( 2.5x4x10) m^3
= 130 kg

7 0

3 years ago

Wavelength of blue photons 495 nm, what is the frequency? and what is the energy?

inessss [21]

Answer:

1.F: About 6*10^14 Hz

2.E: About 4*10^ -19 J

Explanation:

Frequency: We knew that the speed of a wave is its wavelength(λ)* frequency(f, in Hz). By the wave-particle duality we know we can calculate the frequency of light in the same way. So, c=495nm *f, f=c/495nm=> (299,792,458 m/s) / (4.95*10^-7 m)

=6.05*10^14 /s

Energy: The energy photon contains can be calculate by this formula-- E=hf

f is the frequency and h is Planck's constant which is about 6.62 ×10^-34 *m^2*kg/s (after dimensional analysis ) =6.62*10^ -34 J*s.

So, the energy of a blue photon is (6.05*10^14)*(6.62*10^-34)=40.051*10^-20= 4.051*10^-19 J

3 0

2 years ago

While Bob is demonstrating the gravitational force on falling objects to his class, he drops an 1.0 lb bag of feathers from the

BartSMP [9]

In the experiment of free fall bob released a bag of mass 1 lb

so here we can say that initial speed of the bag is Zero

time taken by the bag to free fall is given as

t = 1.5 s

also the acceleration of free fall is given as

a = 9.8 m/s^2

now we will use kinematics equation here for finding the distance of free fall

$d = v_i * t + \frac{1}{2} at^2$

$d = 0 + \frac{1}{2}*9.8* 1.5^2$

$d = 4.9 * 2.25$

$d = 11.025 m$

so the bag will fall down by total distance of 11.025 m from its initial released position.

3 0

3 years ago

A 1500 kg truck travelling north at 60 km/hr collides with a 1200 kg car moving east at 15km/hr. If the two cars remain locked t

Alenkinab [10]

Answer:

33.33j+6.67i km/hr

Explanation:

From the law of conservation of momentum,

Applying,

mu+m'u' = V(m+m')............... Equation 1

Where m = mass of the truck, m' = mass of the car, u = initial velocity of the truck, u' = initial velocity of the car, V = Final velocity.

Note: let j represent the north, and i represent the east

From the question,

Given: m = 1500 kg, u = 60j, m' = 1200 kg, u' = 15i

Substitute these values into equation 1

1500*60j+1200*15i = V(1500+1200)

90000j+18000i = 2700V

V = (90000j+18000i)/2700

V = 33.33j+6.67i km/hr

6 0

2 years ago