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bagirrra123 [75]
4 years ago
12

When you do positive work on an object, you ______

Physics
2 answers:
guajiro [1.7K]4 years ago
4 0

C. increase the object's energy

gtnhenbr [62]4 years ago
3 0

when you do positive work on an object, you ______  

A. decrease the object's energy

<u>B. keep the object's energy the same </u>

C. increase the object's energy

D. may increase or decrease the object's energy

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3 years ago
This graph represents an exothermic reaction. What does it show about the
Zanzabum

The answer is A

Just did it

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3 years ago
Find the momentum of a 3.0 kg mass when it is stopped
lina2011 [118]

Answer:

4,0kg it is stopped!!!!!

3 0
3 years ago
Consider a taut inextensible string. You shake the end of the string with some frequency, causing a wave to travel down the stri
masha68 [24]

Answer:

Part 1:

Option B is correct (It will remain unchanged).

Part 2:

Option C is correct (It will increase by a factor of √ 2)

Part 3:

Option E is correct (It will be half as fast/long.)

Part 4:

Option C is correct (It will increase by a factor of √ 2.)

Explanation:

Formula we are going to use:

V=f*λ

Where:

V is the speed of Sound

f is the frequency of wave

λ is the wavelength.

The speed of wave , tension and linear density have following relation:

V=\sqrt{F/\rho}

Where:

V is the speed of Sound (Initial)

F is the tension in string (Initial)

\rho is the linear density of string (Constant)

Terms:

V' is the new speed

f' is the new frequency

λ' is the wavelength

Solution:

Part 1:

From V=\sqrt{F/\rho}:

Speed of Sound is independent of the frequency of shaking so speed well remain unchanged.

Option B is correct (It will remain unchanged)

Part 2:

If F'=2F then

V=\sqrt{F/\rho}

V'=\sqrt{F'/\rho}\\V'=\sqrt{2F/\rho}\\V'=  \sqrt{2} * \sqrt{F/\rho}\\V'=\sqrt{2}V

Option C is correct (It will increase by a factor of √ 2)

Part 3:

Formula we are going to use:

V=f*λ

Given f'=2f,

Even though frequency is doubled we will keep velocities same. V=V' in order to find the changing wavelength.

V'=f'*λ'

f*λ=f'*λ'

f*λ=2f*λ'

Solving above Equation:

λ'=λ/2

Option E is correct (It will be half as fast/long.)

Part 4:

T'=2T means V'=\sqrt{2}V (From Part 1)

f'=f

Now:

V'=f'*λ'

\sqrt{2}f*\lambda=f'*\lambda '\\\sqrt{2}f*\lambda=f*\lambda '\\ \lambda '=\sqrt{2}*\lambda

Option C is correct (It will increase by a factor of √ 2.)

5 0
3 years ago
A 4.4 nC charge exerts a repulsive force of 36 mN on a second charge which is located
zhenek [66]

The magnitude and sign of the second charge will be + 8.6241×10⁻¹⁹ C. The principal of the Columb's law is used in the given problem.

<h3>What is Columb's law?</h3>

The force of attraction between two charges, according to Coulomb's law, is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

Charges that are similar repel each other, whereas charges that are diametrically opposed attract each other.

They will repel, moving in opposite directions at the same speed. Because the magnitude and nature of the charge are the same.

The given data in the problem is;

q₁  is the charge 1 = 4.4 nC = 4.4 ×10⁻⁹ C

F is the repulsive force = 36 mN =36 ×10⁶ N

d is the distance = 0.70 m

The Coulomb force is found as;

\rm F = \frac{Kq_1q_2}{r^2}\\\\\ \rm 36\times 10^6 = \frac{9 \times 10^9 }{(0.7)^2} \times 4.4 \times 10^{-9} \times q_2\\\\\ q_2 = 8.6241  \times 10^{-19 } \ C

Hence, the magnitude and sign of the second charge will be + 8.6241×10⁻¹⁹ C.

To learn more about Coulomb's law, refer to the link;

brainly.com/question/1616890

#SPJ2

6 0
3 years ago
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