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Alisiya [41]
3 years ago
8

Assume that 10 waves pass a fixed point in 5 seconds. What is the frequency of the waves in hertz?

Physics
1 answer:
dedylja [7]3 years ago
8 0

Answer:

2 hz

Explanation:

Hertz is cps or cycles per second.  10/5= 2 cps

You might be interested in
A heat engine has a maximum possible efficiency of 0.780. If it operates between a deep lake with a constant temperature of-24.8
Volgvan

Answer : The temperature of the hot reservoir (in Kelvins) is 1128.18 K

Explanation :

Efficiency of carnot heat engine : It is the ratio of work done by the system to the system to the amount of heat transferred to the system at the higher temperature.

Formula used for efficiency of the heat engine.

\eta =1-\frac{T_c}{T_h}

where,

\eta = efficiency = 0.780

T_h = Temperature of hot reservoir = ?

T_c = Temperature of cold reservoir = -24.8^oC=273+(-24.8)=248.2K

Now put all the given values in the above expression, we get:

\eta =1-\frac{T_c}{T_h}

0.780=1-\frac{248.2K}{T_h}

T_h=1128.18K

Therefore, the temperature of the hot reservoir (in Kelvins) is 1128.18 K

8 0
3 years ago
A baseball leaves a bat with a horizontal velocity of 20 m/s. In a time of 0.25 s, How far will it have traveled horizontally?
Maurinko [17]

Distance traveled by the ball is given by

distance = speed \times time

here we know that

speed = 20 m/s

times = 0.25 s

now we have

distance = 20 \times 0.25

distance = 5 m

so ball will travel 5 m distance in the given interval of time

6 0
3 years ago
An ice-making machine inside a refrigerator operates in a Carnot cycle. It takes heat from liquid water at 0.0 ∘C and rejects he
Agata [3.3K]

Answer:

2.36 x 10^6 J

Explanation:

Tc = 0°C = 273 K

TH = 22.5°C = 295.5 K

Qc = heat used to melt the ice

mass of ice, m = 85.7 Kg

Latent heat of fusion, L = 3.34 x 10^5 J/kg

Let Energy supplied is E which is equal to the work done

Qc = m x L = 85.7 x 3.34 x 10^5 =  286.24 x 10^5 J

Use the Carnot's equation

\frac{Q_{H}}{Q_{c}}=\frac{T_{H}}{T_{c}}

Q_{H}=286.24\times 10^{5}\times \frac{295.5}{273}

QH = 309.8 x 10^5 J

W = QH - Qc

W = (309.8 - 286.24) x 10^5

W = 23.56 x 10^5 J

W = 2.36 x 10^6 J

Thus, the energy supplied is 2.36 x 10^6 J.

8 0
3 years ago
30 points plz help ill do anything... literally anything.
ruslelena [56]

Answer:

1. 2.5s

Explanation:

1. For time, divide Distance / speed

25m / 10

=2.5s

3 0
3 years ago
100 Points !!!!!!!! I WILL GIVE BRAINLIEST
kumpel [21]

Answer: 1. 0.25 m/s squared

2. A = 0.4 m/s^2

3.=20kg. I did this before.

Explanation:

3 0
3 years ago
Read 2 more answers
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