10186.28
And that’s how you do it
Katia and Thomasina play a computer game and record these scores. Katia: 8, 6, -4, -7, 2, 0, 3 Thomasina: -11, 0, 8, 7, 5, -7, 1
suter [353]
Answer:
Step-by-step explanation:
there is no factorization of y^2 -2y +35 in real numbers
Thomasina correctly determined two factors of 35 that differ by 2, but that is not what is needed here. For this problem, she needs two factors of 35 that have a sum of 2.* (There aren't any real-number factors that meet that condition.)
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The factorization in complex numbers would be ...
= (y -1 -i√34)(y -1 +i√34)
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* Technically, she needs two factors of 35 with a sum of -2. Both factors would have to be negative.
It would be 600 miles in 24 hours if it continues to fly at the same speed cause every 2 hours the distance goes up by 50.
It would be equivalent to 18/22 as double 11 is 22 so we just do the same to the numerator (double)
Diagonal of a Rhombus are perpendicular & intersects in their middle point:
Assume the diagonals intersects in H
A(0,-8), B(1,-0), C(8,-4) & D(x, y) are the vertices of the rhombus and we have to calculate D(x, y)
Consider the diagonal AC. Find the coordinate (x₁, y₁) H, the middle of AC
Coordinate (x₁, y₁) of H, middle of A(0,-8), C(8,-4)
x₁ (0+8)/2 & y₁=(-8-4)/2 ==> H(4, -6)
Now let's calculate again the coordinate of H, middle of the diagonal BD
B(1,-0), D(x, y)
x value = (1+x)/2 & y value=(y+0)/2 ==> x= (1+x)/2 & y=y/2
(1+x)/2 & y/2 are the coordinate of the center H, already calculated, then:
H(4, -6) = [(1+x)/2 , y/2]==>(1+x)/2 =4 ==> x=7 & y/2 = -6 ==> y= -12
Hence the coordinates of the 4th vertex D(7, -12)
