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Makovka662 [10]
3 years ago
13

Y + (-3 y2 ) +2( y2 - 6y) simplify​

Mathematics
1 answer:
labwork [276]3 years ago
3 0

Answer:

y - 3y^2 + 4y^2 - 12y

y^2 - 11y

Step-by-step explanation:

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I think B or F is the best answer

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1 1/5 to the power of 3-1
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This is 6/5 to the 2 (6/5 squared). 36/25 is the answer
4 0
4 years ago
The lengths of the diagonals of a rhombus are 2 inches and 5 inches. Find the measures of the angles of the rhombus to the neare
Radda [10]
2arctan(2/5) = 44°
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The angles are 44°, 136°.
4 0
3 years ago
Evaluate the expression x + (-5) +5 when x=-3<br> 4x12
Anastasy [175]

Answer:

2045

Step-by-step explanation:

-34×12(-5)+5

-405(-5)+5

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2045 is the answer

5 0
3 years ago
The area of a rectangular television screen is 3456 in^2. The width of that screen is 24 inches longer than the length. What is
shutvik [7]
1. The problem says that the television has a rectangular shape. So, the formula for caculate the area of a rectangle is:

 A=LxW

 "A" is the area of the rectangle (A=3456 inches²).
 "L" is the the length of the rectangle.
 "W" is the width of the rectangle.

 2. The <span>width of the screen is 24 inches longer than the length. This can be expressed as below:

 W=24+L

 3. Then, you must substitute </span>W=24+L into the formula A=LxW:
<span>
 </span>A=LxW
<span> 3456=L(24+L)
 3456=24L+L</span>²
<span>
 4. The quadratic equation is:

 L</span>²+24L-3456=0

 5. When you solve the quadratic equation, you obtain:

 L=48 inches

 6. Finally, you must substitute the value of the length, into W=24+L:

 W=24+L
 W=24+48
 W=72 inches

 7. Therefore, the dimensions of the screen are:

 L=48 inches
 W=72 inches<span> </span>
4 0
3 years ago
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