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3 years ago

Please help me and show your wprk

Mathematics

1 answer:

stellarik [79]3 years ago

3 0

This is how I find the GCF.

I find the prime factors.

63/3 = 21
21/3 = 7
7/7 = 1

81/3 = 27
27/3 = 9
9/3 = 3
3/3 = 1

Then I find the common prime factors:
63: 3 x 3 x 7
81: 3 x 3 x 3 x 3

Then I multiply the common prime factors:
3 x 3 = 9

The GCF for 63 and 81 (number 3) is 9.

I bet you can use this method for all the other GCFs! :)

For this one, find the prime factors like before, and if there aren't any besides one, then it's a prime number.

75/3 = 25
25/5 = 5
5/5 = 1

The prime factorization for 75 is 3 x 5 x 5

(I don't know the answer to 7, 8, 9, 10, 11, 12, 25, or 26, sorry!)

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explanation:
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A hiker walks at a speed of 3 2/5 kilometers per hour. How many kilometers will the hiker walk-in 3/4 hours?

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2 years ago

In the past, the mean running time for a certain type of flashlight battery has been 9.7 hours. The manufacturer has introduced

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Answer:

Step-by-step explanation:

From the information given:

$\mathbf{H_o: \mu = 9.7 \ hours}$

$\mathbf{H_1: \mu > 9.7 \ hours}$

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2 years ago

Classify the Polynomial by its number of terms.

Ivenika [448]

Answer:

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2 years ago

Please help me. This is real confusing.

katrin2010 [14]

Answer:

1st problem: b) $A=2500(1.01)^{12t}$

2nd problem: c) $A=2500e^{.12t}$

Step-by-step explanation:

1st problem:

The formula/equation you want to use is:

$A=P(1+\frac{r}{n})^{nt}$

where

t=number of years

A=amount he will owe in t years

P=principal (initial amount)

r=rate

n=number of times the interest is compounded per year t.

We are given:

P=2500

r=12%=.12

n=12 (since there are 12 months in a year and the interest is being compounded per month)

$A=2500(1+\frac{.12}{12})^{12t}$

Time to clean up the inside of the ( ).

$A=2500(1+.01)^{12t}$

$A=2500(1.01)^{12t}$

----------------------------------------------------

2nd Problem:

Compounded continuously problems use base as e.

$A=Pe^{rt}$

P is still the principal

r is still the rate

t is still the number of years

A is still the amount.

You are given:

P=2500

r=12%=.12

Let's plug that information in:

$A=2500e^{.12t}$ .

6 0

2 years ago