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yKpoI14uk [10]
4 years ago
10

Please help me and show your wprk

Mathematics
1 answer:
stellarik [79]4 years ago
3 0
This is how I find the GCF.

I find the prime factors. 

63/3 = 21
21/3 = 7
7/7 = 1 

81/3 = 27
27/3 = 9
9/3 = 3
3/3 = 1

Then I find the common prime factors:
63: 3 x 3 x 7
81: 3 x 3 x 3 x 3 

Then I multiply the common prime factors:
3 x 3 = 9

The GCF for 63 and 81 (number 3) is 9. 

I bet you can use this method for all the other GCFs! :)

For this one, find the prime factors like before, and if there aren't any besides one, then it's a prime number. 

75/3 = 25
25/5 = 5
5/5 = 1
 
The prime factorization for 75 is 3 x 5 x 5

(I don't know the answer to 7, 8, 9, 10, 11, 12, 25, or 26, sorry!)


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What does this equation equal? <br> 4-2(-2)+(-2)=
Zielflug [23.3K]
This equation equals 6.
5 0
4 years ago
The given measurements may or may not determine a triangle. If not, then state that no triangle is formed. If a triangle is form
ZanzabumX [31]
Draw ΔABC as shown in the figure below.
m∠B = 137°, b = 14, c = 9.

From the Law of Sines,
sin(C)/c = sin(B)/b
or
sin(C)/9 = sin(137°)/14
sin(C) = (9/14)*sin(137°) = 0.4384
m∠C = arcsin(0.4384) = 26°

Because the sum of angles in a triangle is 180°, therefore
m∠A = 180 -137 - 26 = 17°

From the Law of Sines,
a/sin(A) = b/sin(B)
or
a/sin(17°) = 14/sin(137°)
a = (sin(17°)/sin(127°))*14 = 6

Answer:
The solution for the triangle is
a = 6,         b = 14,           c = 9
m∠A = 17°, m∠B = 137°, m∠C = 26°

3 0
3 years ago
I need for that questions ?
matrenka [14]
Im unable to send the equation

8 0
4 years ago
g Farmer Violet wants to enclose one 990 square foot rectangular area of land using fencing. One side will use special fencing c
saw5 [17]

Answer:

Sides of the rectangular area:

x =  30  f

y =  33  f

Step-by-step explanation:

Let´s call   x  and y the sides of the rectangular area

A = x*y  = 990          y  = 990/x

The function cost is:

C = Costs ( sides x)  + costs ( sides y )

Cost of sides x    =  12*x +  10x

Cost of sides y    =  10*y  +  10 *y   =  2*10*y  = 20*y

C = 12*x + 10*x + 20*y =  22*x  + 20*y

The function cost as function of x is:

C(x)  = 22*x + 20*(990/y)  =  22*x  +  19800/x

Tacking derivative on both sides of the equation:

C´(x)  = 22  + [ - 19800/x²]

C´(x) = 0       22  - 19800/x²  =  0

Solving for x

22*x²  - 19800  =  0

22x²  =  19800

x² =  19800/22 =  900

x₁,₂ = ± 30        We dismiss negative root ( we never have negative lenghts)

Then     x =  30 f

And  y  =  990 / 30      y  = 33  

To see if x = 30 is a minimum for function C(x) we evaluate the second derivative.

C´´(x) = 2*x* 19800/x⁴      

C´´ (x) = 39600/x³    so C´´ is always greater than 0 then C (x) has a minimum at x = 30

Sides of the rectangular area are:

x  =  30

y  =  33

6 0
3 years ago
Substitutions <br> y=x+4<br> y=3x+0
cluponka [151]

Answer:

x = 2

Step-by-step explanation:

since both equal y, you can set them equal to each other

x + 4 = 3x + 0

subtract x on both sides

4 = 2x

divide by 2 on both sides

2 = x

♡♡ hope this helped ♡♡

4 0
3 years ago
Read 2 more answers
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