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weqwewe [10]
3 years ago
13

True or false? In a two column proof, the right column states your reasons

Mathematics
2 answers:
nikdorinn [45]3 years ago
8 0

False. A two-column proof is also known as a "Statement-Reason Proof", with the statement column on the left and the reason column on the right.
Yuri [45]3 years ago
7 0

Answer:

True

Step-by-step explanation:

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PLS ANSWER QUICK! Thanks!
ziro4ka [17]

Answer:

The correct answer would be a=\sqrt{c^2-b^2}

Step-by-step explanation:

given a^2+b^2=c^2 we want to solve for a

How?

We can do this by using basic algebra ( isolating the variable (a ))

Step 1 subtract b^2 from each side

a^2+b^2-b^2=a^2\\c^2-b^2=c^2-b^2

now we have a^2=c^2-b^2

step 2 take the square root of each side

\sqrt{a^2} =a\\\sqrt{c^2-b^2} =\sqrt{c^2-b^2}

we're left with a=\sqrt{c^2-b^2}

Hence your answer is A

5 0
3 years ago
What is the equation in slope-intercept form of the line that passes through the points (-4.2) and (12, 6)? (2 points)
sp2606 [1]

Answer: that's hard

Step-by-step explanation:that's hard

7 0
2 years ago
Solve 5c + 4 = -26
mr_godi [17]
<em>1) 5 c + 4 = - 26
5 c = -26 -4
5 c = -30
c = -30 / 5
c = -6    so correct option is B..

2) 3 x - x +2 = 12
2 x +2 = 12
2x = 12-2
2x = 10
x = 10/2
x= 5    so correct option is D

3 ) 3 ( x + 1 )+ 6 = 33
3x + 3 + 6 = 33
3x + 9 = 33
3x = 33-9
3x = 24
x = 24/3
x = 8   so correct option is B

4) y/-6=9
y=9 x -6
y= - 54   there is no such option i guess question is missing

5)(x +  4) /2 = 7
x +4 = 7 x 2
x + 4 = 14
x = 14-4
x = 10  so correct option is D

6)1/3 ( 2x - 8) = 4
2x/ 3 - 8 /3 = 4
2x - 8 / 3 = 4
2x - 8 = 4 x 3
2x - 8 = 12
2x = 12 + 8
2x = 20
x = 20/2
x = 10   so correct option is C


</em>
6 0
3 years ago
I dont remember these type of questions in Geometry can anyone help
Greeley [361]

the answer is 120 bc 140 is adjacent to it and 140-20 = 120

3 0
3 years ago
Read 2 more answers
Pleaseee helppp I don't understand thissd
Bess [88]

Very simple.

Let's say you have an equation.

f(x) = x^2

You are asked to find the value for y when x equals 1.

The new equation is: f(1) = (1)^2

f(1) = 1

When x = 1, y = 1.

The same concept is applied here.

In the graph, where does x equal 0?

It equals zero at the origin.

Is there any y-value associated with 0?

Yes, there is.

Y equals five when x equals 0.

So

h(0) = 5

6 0
3 years ago
Read 2 more answers
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