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3 years ago

Math question (working too, if possible)

Mathematics

2 answers:

inessss [21]3 years ago

4 0

4/15 of the Primary School chose chicken nuggets.

TiliK225 [7]3 years ago

3 0

Add the fractions that chose fish fingers and burgers, then subtract that sum from 1.

Fish fingers: 2/5

Burgers: 1/3

Sum of fish fingers and burgers fractions:

2/5 + 1/3

Common denominator = 15

2/5 * 3/3 + 1/3 * 5/5 = 6/15 + 5/15 = 11/15

Now we subtract 11/15 from 1.

1 - 11/15 = 1/1 * 15/15 - 11/15 = 4/15

The fraction that chose chicken nuggets is 4/15.

You might be interested in

In triangle ABC, Aat the top of the triangle, B at 90° and C at the third end, angle C = 21°, the hypotenus = 15m,find BC = y th

dsp73

Answer

Step-by-step explanation:

Law of sines: SinB/15 = SinA/BC

B = 90

A = 180-90-21=69°

BC= (15*SinA)/SinB = (15*sin69)/1 ≈ 14m

7 0

2 years ago

A circle has a diameter of 26 units. What is the area of the circle to the nearest hundred of a square unit?

Nady [450]

Answer: The area is 530 square units

Step-by-step explanation: The diameter of the circle has been given as 26. That makes the radius 13, that is;

Radius = diameter/2

Radius = 26/2

Radius = 13

The area of a circle is derived by the formula;

Area = pi x r^2

Where pi is 3.14 and r is 13,

Area = (3.14) x 13^2

Area = 3.14 x 169

Area = 530.66

Approximately to the nearest hundred of a square unit,

The area of the circle is 530 square units

5 0

3 years ago

Read 2 more answers

The floor of a triangular room has an area of 32 1/2 sq.m. If the triangle’s altitude is 7 172 m, write an equation to determine

sineoko [7]

Answer:

$\frac{(2)A}{h} =b$

b=0.00906m

Step-by-step explanation:

Hello! To solve this exercise we must remember that the area of any triangle is given by the following equation

$A=\frac{bh}{2}$

where

A=area=32.5m^2

h=altitude=7172m

b=base

Now what we should do take the equation for the area of a rectangle and leave the base alone, remember that what we do on one side of the equation we must do on the other side to preserve equality

$A=\frac{bh}{2} \\\frac{2}{h} A=\frac{bh}{2} \frac{2}{h} \\$

$\frac{A(2)}{h} =b$

solving

$\frac{2(32.5)}{7172} =0.0090[tex]\frac{A(2)}{h} =b\\b=0.00906m$

4 0

3 years ago

Need help!!! Plzzz Help mee

andrew-mc [135]

Okay what you need I’ll help you with whatever

8 0

3 years ago

One more time!

CaHeK987 [17]

Since q(x) is inside p(x), find the x-value that results in q(x) = 1/4

$\frac{1}{4} = 5 - x^2\ \Rightarrow\ x^2 = 5 - \frac{1}{4}\ \Rightarrow\ x^2 = \frac{19}{4}\ \Rightarrow \\
x = \frac{\sqrt{19} }{2}$

so we conclude that
$q(\frac{\sqrt{19} }{2} ) = 1/4$

therefore

$p(1/4) = p\left( q\left(\frac{ \sqrt{19} }{2} \right) \right)$

plug $x=\sqrt{19}/2$ into p( q(x) ) to get answer

$p(1/4) = p\left( q\left( \frac{ \sqrt{19} }{2} \right) \right)\ \Rightarrow\ \dfrac{4 - \left( \frac{\sqrt{19} }{2}\right)^2 }{ \left( \frac{\sqrt{19} }{2}\right)^3 } \Rightarrow \\ \\ \dfrac{4 - \frac{19}{4} }{ \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{8\left(4 - \frac{19}{4}\right) }{ 8 \cdot \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{32 - 38}{19\sqrt{19}} \Rightarrow \dfrac{-6}{19\sqrt{19}} \cdot \frac{\sqrt{19}}{\sqrt{19}}\Rightarrow$

$\dfrac{-6\sqrt{19} }{19 \cdot 19} \\ \\ \Rightarrow -\dfrac{6\sqrt{19} }{361}$

$p(1/4) = -\dfrac{6\sqrt{19} }{361}$

3 0

3 years ago