Question

As a plane takes off it ascends at a 20 degree angle of elevation. If the plane has been traveling at an average rate

Answer 1

Answer:

The plane was 923.5 feet high after 10 seconds.

Step-by-step explanation:

Angle made by plane with ground during take off = x = 20°

Average speed of plane = 270 ft/s

Let the height of Plane after 10 seconds from the takeoff = H

Distance covered by plane in 10 seconds = 270 ft/s × 10 sn= 2700 ft

According to trigonometric ratios:

$\Sin \theta=\frac{Perpendicular}{Hypotenuse}$

Here , perpendicular = H

Hypotenuse = 2700 ft

$\Sin 20^o=\frac{H}{2700 ft}$

$H=0.342020\times 2700 ft=923.45 ft\approx 923.5 ft$

The plane was 923.5 feet high after 10 seconds.

Answer 2

the answer is A.) 923.5 feet