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3 years ago

How many grams of KCl is produced if 32.4 grams of O2 is produced?

1 answer:

8 0

Okay so, the molar mass (Mr) of O2 is 32g

moles = mass/Mr
moleS= 32.4/32= 1.0125mol
the Mr of KCl is 39.1+35.5= 74.6g

the ratio of moles of KCl to O2 is 2 : 3
therefore moles of KCl is (1.0125/3)×2= 0.675mols

mass =moles×Mr=0.675×74.6= 50.355g
rounds up to 50.3g therefore last answer is correct

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Answer: $101.9^0C$

Explanation:

Elevation in boiling point is given by:

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$(T_b-100)^0C=3\times 0.512\times \frac{175.0g}{142g/mol\times 1.000kg}$

$T_b=101.9^0C$

Thus the boiling point of water when 175.0 g of $Na_2SO_4$ , a strong electrolyte is dissolved in 1.000 Kg of water is $101.9^0C$

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An object weighting 9.6 grams is placed in a graduated cylinder displacing the volume from 10.0mL to 13.2 mL

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The volume of object is 3.2 ml

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Given:

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