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never [62]
2 years ago
7

How many grams of KCl is produced if 32.4 grams of O2 is produced?

Chemistry
1 answer:
MrRissso [65]2 years ago
8 0
Okay so, the molar mass (Mr) of O2 is 32g

moles = mass/Mr
moleS= 32.4/32= 1.0125mol
the Mr of KCl is 39.1+35.5= 74.6g

the ratio of moles of KCl to O2 is 2 : 3
therefore moles of KCl is (1.0125/3)×2= 0.675mols

mass =moles×Mr=0.675×74.6= 50.355g
rounds up to 50.3g therefore last answer is correct


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Answer:

<h2>7.54 atm </h2>

Explanation:

The required pressure can be found by using the formula for Boyle's law which is

P_2 =  \frac{P_1V_1}{V_2}  \\

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

From the question we have

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We have the final answer as

<h3>7.54 atm </h3>

Hope this helps you

3 0
2 years ago
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MrMuchimi
To solve this problem we just need to use the rule of three:
150g..................395.1J
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x = 450*395.1/150 = 1185,3J

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