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3 years ago

5

What forces come in pairs? Give an example help ASAP

1 answer:

kondor19780726 [428]3 years ago

3 0

Action and reaction forceZ

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Show the equation of simple pendulum to be dimensionally consistent

nataly862011 [7]

T is in seconds (s)

<span>2pi is dimensionless </span>

<span>L is in meters (m) </span>

<span>g is in meters per second squared (m/s^2) </span>

<span>so you can write the equation for the period of the simple pendulum in its units... </span>

<span>s=sqrt(m/(m/s^2)) </span>

<span>simplify</span>

<span>s=sqrt(m*s^2*1/m) cancelling the m's </span>

<span>s=sqrt(s^2) </span>

<span>s=s </span>

<span>therefore the dimensions on the left side of the equation are equal to the dimensions on the right side of the equation.</span>

6 0

3 years ago

If F1 is the magnitude of the force exerted

aleksandrvk [35]

Answer: 3. F1 = F2

Explanation:

According to <u>Newton's law of Gravitation</u>, the force $F$ exerted <u>between two bodies</u> or objects of masses $M$ and $m$ and separated by a distance $r$ is equal to the product of their masses divided by the square of the distance:

$F=G\frac{Mm}{r^2}$ (1)

Where $G$ is the gravitational constant

Now, in the especific case of the Earth and the satellite, where the Earth has a mass $M$ and satellite a mass $m$ , being both separated a distance $r$ , the force exerted by the Earth on the satellite is:

$F1=G\frac{Mm}{r^2}$ (2)

And the force exerted by the satellite on the Earth is:

$F2=G\frac{Mm}{r^2}$ (3)

As we can see equations (2) and (3) are equal, hence the magnitude of the gravitational force is the same for both:

$F1=F2$

3 0

3 years ago

Your soccer team needs to add a new player midseason. Which of these people would most likely demonstrate good sportsmanship bas

Irina18 [472]

Jasper, because he developed friendships playing with everyone last year,

Thats the answer

5 0

3 years ago

Read 2 more answers

Fellow student of mathematical bent tells you that the wave function of a traveling wave on a thin rope is y(x,t)= 2.20 mm cos[(

bezimeni [28]

Answer

given,

y(x,t)= 2.20 mm cos[( 7.02 rad/m )x+( 743 rad/s )t]

length of the rope = 1.33 m

mass of the rope = 3.31 g

comparing the given equation from the general wave equation

y(x,t)= A cos[k x+ω t]

A is amplitude

now on comparing

a) Amplitude = 2.20 mm

b) frequency =

$f = \dfrac{\omega}{2\pi}$

$f = \dfrac{743}{2\pi}$

f = 118.25 Hz

c) wavelength

$k= \dfrac{2\pi}{\lambda}$

$\lambda= \dfrac{2\pi}{k}$

$\lambda= \dfrac{2\pi}{7.02}$

$\lambda= 0.895\ m$

d) speed

$v = \dfrac{\omega}{k}$

$v = \dfrac{743}{7.02}$

v = 105.84 m/s

e) direction of the motion will be in negative x-direction

f) tension

$T = \dfrac{v^2\ m}{L}$

$T = \dfrac{(105.84)^2\times 3.31 \times 10^{-3}}{1.33}$

T = 27.87 N

g) Power transmitted by the wave

$P = \dfrac{1}{2}m\ v \omega^2\ A^2$

$P = \dfrac{1}{2}\times 0.00331\times 105.84\times 743^2\ 0.0022^2$

P = 0.438 W

5 0

3 years ago

List 1 chemical property of a metal a nail?

timurjin [86]

Iron...................... hope this helpes

8 0

3 years ago