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vladimir1956 [14]
3 years ago
5

The coordinates of a bird flying in the xy plane are given by x(t)=αt and y(t)=3.0m−βt2, where α=2.4m/s and β=1.2m/s2. Calculate

the velocity vector of the bird as a function of time.
Physics
2 answers:
cluponka [151]3 years ago
6 0

Answer : The velocity vector of the bird as a function of time 2.4\sqrt{1+t^2}

Solution :

x(t)=\alpha t\\\\\frac{dx}{dt}=\alpha

The x-component is, \frac{dx}{dt}=\alpha

y(t)=3.0m-\beta t^2\\\\\frac{dy}{dt}=-2\beta t

The y-component is, \frac{dy}{dt}=-2\beta t

Now we have to calculate the velocity vector of the bird as a function of time.

\overset{\rightarrow}V=\sqrt{x^2+y^2}

Now put the values of x-component and y-component in this equation, we get

\overset{\rightarrow}V=\sqrt{x^2+y^2}=\sqrt{(\alpha)^2+(-2\beta t)^2}=\sqrt{(2.4)^2+(-2\times 1.2\times t)^2}=2.4\sqrt{1+t^2}

Therefore, the velocity vector of the bird as a function of time 2.4\sqrt{1+t^2}

yuradex [85]3 years ago
4 0
     The derivative of the function space as a function of time is equal to a function of speed as a function of time.

x(t)=2.4t \\  \frac{x(t)}{t}=t \\ v_{x}(t)=t \\  \\ y(t)=3-1.2\times t^2 \\  \frac{y(t)}{t}=1.2\times2t \\ v_{y}(t)=2.4t
   
     The velocity vector is given by the vector sum of the velocities of  both axes.

v_{R}^2(t)=v_{x}^2(t)+v_{y}^2(t) \\ v_{R}^2(t)=(t)^2+(2.4t)^2 \\ \boxed {v_R(t)=2.6t}

If you notice any mistake in my english, please let me know, because I am not native.

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Explanation:

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