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Len [333]
3 years ago
14

A fire hose is made of six sections, each 15 feet in length. The sections are joined together with Storz couplings, which are fo

ur inches long each. What is the total length of the hose?
Physics
1 answer:
gayaneshka [121]3 years ago
8 0

Answer:

h=740\ in

Explanation:

Given:

length of each pipe section, l=15\ ft=180\ in

length of each coupling, c=4 \ in

Now according to question we have six hoses which will require 5 couplings to join them.

So the total length of the hose:

h=6\times l+5\times c

h=6\times 180+5\times 4

h=740\ in is  the total length of the hose.

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Steam at 400C has a specific volume of 0.02m3/kg. Determine the pressure of the steam based on a) the ideal gas equation b) the
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Answer:

by ideal gas pressure = 15529.475 kPa

by compressibility chart pressure = 12576 kPa

by steam tables Pressure = 12517 kPa

Explanation:

given data

temperature T = 400°C = 673 K

volume v = 0.02 m³/kg

to find out

pressure by ideal gas, compressibility chart and steam tables

solution

we know here by table

gas constant R is 0.4615 kJ/ kg-K

and critical temp Tc = 647.1 K

and critical pressure Pc = 22064 kPa

so by ideal gas pressure is

pressure = R×T / v

pressure = 0.4615 × 673  / 0.02

pressure = 15529.475 kPa

and

by compressibility chart

temperature reduce is = T/ Tc

temperature reduce Tr = 673 / 647.1

Tr = 1.040 K

so pseudo reduce volume is here

reduce volume Vr = v / ( RTc/Pc)

reduce volume Vr =\frac{0.02}{\frac{461.5(647.1)}{22064*10^{3} } }

0.02 / ( 461.5(647.1) / 22064×10³)

reduce volume = 1.48

and we know by compressibility chart

reduce pressure Pr is 0.57

so

pressure = Pr × Pc

pressure = 0.57 × 22064 ×  10³

pressure = 12576 kPa

and

from steam table

pressure is 12.5 MPa at 673 K and 0.020030 m³/kg

pressure is 15 MPa at 673 K and 0.015671 m³/kg

so

pressure P is

\frac{0.02 - 0.020030}{0.015671 - 0.020030} = \frac{ P - 12.5}{15 - 12.5}

so

Pressure = 12517 kPa

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Consider Compton Scattering with visible light.A photon with wavelength 500nm scatters backward(theta=180degree) from a free ele
JulijaS [17]

Answer: 4.86(10)^{-12}m

Explanation:

The Compton Shift \Delta \lambda in wavelength when photons are scattered is given by the following equation:

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Where:  

\lambda'=500 nm=500(10)^{-9} m is the wavelength of the scattered photon

\lambda_{o}  is the wavelength of the incident photon

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\Delta \lambda=2.43(10)^{-12} m (1-cos(180\°)) (2)

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