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noname [10]
3 years ago
7

Given f(x)= 4x^3 -x-7 , what is the value of x in the interval [1, 1.5] for which the function takes the value 1?

Mathematics
1 answer:
azamat3 years ago
8 0

Answer:

1.326

Step-by-step explanation:

4x³-x-7 = 1

4x³-x-8 = 0

x ≅ 1.326, -0.663+1.034i, -0.663-1.034i

-0.663+1.034i and -0.663-1.034i are extraneous solutions.

x ≅ 1.326

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