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tia_tia [17]
3 years ago
12

A certain car traveling in a straight line path has a velocity of +10.0 m/s at some instant. after 3.00 s, its velocity is +6.00

m/s. what is the average acceleration of the car during this time interval?
Physics
1 answer:
makvit [3.9K]3 years ago
3 0
The formula is:
v = v o + a t
6 = 10 + 3 * a
3 a = 10 - 6
a = 4 : 3
a =  - 1.33 m/s² ( because the car slows down )
Answer: The average acceleration of the car is - 1.33 m/s²
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V=\frac{4}{3} \pi(r_2^3-r_1^3)

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A student pushes a 12.0 kg box with a horizontal force of 20 N. The friction force on the box is 9.0 N. Which of the following i
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The acceleration of the box is approximately 1 m/s^2

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The net force can be written as

\sum F = F_a - F_f

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F_a = 20 N is the applied forward force

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Combining the two equations,

F_a-F_f=ma

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a=\frac{F_a-F_f}{m}=\frac{20-9}{12}=0.9 m/s^2\sim 1 m/s^2

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

8 0
3 years ago
Two spherical objects have masses of 6.2 x 105 kg and 13 x 103 kg. The gravitational attraction between them is 130 N. How far a
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Answer:

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