Question

A certain car traveling in a straight line path has a velocity of +10.0 m/s at some instant. after 3.00 s, its velocity is +6.00 m/s. what is the average acceleration of the car during this time interval?

Answer 1

The formula is:
v = v o + a t
6 = 10 + 3 * a
3 a = 10 - 6
a = 4 : 3
a =  - 1.33 m/s² ( because the car slows down )
Answer: The average acceleration of the car is - 1.33 m/s²