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OlgaM077 [116]
3 years ago
14

Morning friends!! hope y'all have a good day!

Physics
1 answer:
Liula [17]3 years ago
6 0

Answer:

Goid morning

Thanks

U too❤️

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From what height must an oxygen molecule fall in a vacuum so that its kinetic energy at the bottom equals the average energy of
alexandr1967 [171]

Answer:

The  value is  h  = 11930 \ m

Explanation:

From the question we are told that

    The  temperature is  T  =  300 \  K

     

Generally the root mean square speed of the  oxygen molecules is mathematically represented as

        v  =  \sqrt{\frac{3 *  R  *  T }{M} }  =  \sqrt{ 2 *  g  *  h }

Here  R is the gas constant with a value  R  =  8.314 \  J\cdot K^{-1} \cdot \  mol^{-1}

    M  is the molar mass of oxygen molecule with value M  =  0.032 \  kg /mol

So  

     \frac{3 *  8.314   *  300 }{0.032}   =  2 *  9.8  *  h

=>    h  = 11930 \ m

   

4 0
3 years ago
According to newton’s second law of motion, the acceleration of an object equals the net force acting on the object divided by t
Ugo [173]
C mass I am pretty sure
3 0
3 years ago
Read 2 more answers
A person that is sleeping on her stomach rolls over so that she is now sleeping on her back. The person moved from the ________
Elza [17]

Answer:

c. prone; supine

Explanation:

3 0
2 years ago
A wheel rotating about a fixed axis has a constant angular acceleration of 4.0 rad/s2. In a 4.0-s interval the wheel turns throu
anastassius [24]

Answer:

a. 3 s.

Explanation:

Given;

angular acceleration of the wheel, α = 4 rad/s²

time of wheel rotation, t = 4 s

angle of rotation, θ = 80 radians

Apply the kinematic equation below,

\theta = \omega_1 t \ + \ \frac{1}{2} \alpha t^2\\\\80 = 4\omega_1 + \frac{1}{2}*4*4^2\\\\80 = 4\omega_1 + 32\\\\ 4\omega_1 = 48\\\\ \omega_1 = \frac{48}{4}\\\\ \omega_1 = 12 \ rad/s

Given initial angular velocity, ω₀ = 0

Apply the kinematic equation below;

\omega_1 = \omega_o + \alpha t_1\\\\12 = 0 + 4t\\\\4t = 12\\\\t = \frac{12}{4}\\\\t = 3 \ s

Therefore, the wheel had been in motion for 3 seconds.

a. 3 s.

8 0
3 years ago
If a sound wave travels 680 m in 2 seconds and has a frequency of 400 hz, what is the wavelength of the wave?
Kipish [7]

Answer: 0.85 meters (with and without sigfigs)

Explanation: To find the wavelength, you just have to switch around the equation for wave speed: v (wave speed) = λ (wavelength)*f (frequency) so λ (wavelength) = v (wave speed)/f (frequency). You don't have the wave speed but you can calculate it. Since wave speed is measured in meters/second or m/s, you just have to divide the amount of meters you were given by the amount of seconds. You will get 340 m/s. Next, you have to plug the values into the equation: λ (wavelength) = 340 m/s (wave speed)/400 Hz (frequency). The answer is 0.85 meters (seconds cancel) and has the correct number of significant figures.

5 0
3 years ago
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