Answer:
density
Explanation:
pressure within a liquid a liquid only depends on the density of the liquid,the acceleration due to gravity, and the depth within the liquid
Draw a vector diagram. The net force on particle 1 = F12 + F13 + F14 These forces have to be added as vectors.
We will resolve our forces along the direction 1-4 F12 (tot) = -kQq / a^2 in the direction of particle 4 F12 = -kQq *sin (45) / a^2 F12 = -kQq /( a^2 * sqrt(2) )
By symetry this is the same as F13 F13 = -kQq /( a^2 * sqrt(2) )
F14 = -kQQ / (Sqrt(2)*a) ^ 2
For net force on particle 1 :
F12+F13+F14 = 0 -2kQq /( a^2 * sqrt(2) ) + -kQQ / (Sqrt(2)*a) ^ 2 = 0
Some simple manipulation should give you :
Q/q = -2 sqrt(2)
The magnitude of the average force exerted on the ball by the wall is calculated below.
The average force exerted by the ball on the wall is 3 N
Explanation:
Given:
mass of the ball (m)=0.10 kg
speed (v) =3.0 m/s
time taken(t) =0.01 seconds
To calculate:
Average force(F) exerted by ball on the wall
We know;
F=(m×v)÷t
F=(0.10×3.0)÷0.01
<u><em>F=3 N</em></u>
Therefore the average force exerted by the ball on the wall is 3 N
W=(75kg)(9.8m/s^2
W = 735N
