"If air in a pump is squeezed more, then the air gets hotter because energy is added to it" is a good hypothesis that could lead to new experimentation.
<u>Option: C</u>
<u>Explanation:</u>
If we use a pump to inflate a basketball, we initially pull the handle to draw air to fill the sphere in. As we move it down we apply a great deal of force to pump in air through the pin's tiny hole because of this resistance force in the air we find the tube warmed.
A needle of ball pump is a metal tube in which air, from an inflating pump to a sports ball, moves through it. In continuous-flow operation, pumps are often used and built to produce comparatively little pressure towards a free-flowing environment with limited back pressure. Such pumps have a fixed configuration and work freely along their power curve as circumstances change.
Answer:
True. Diffusion and osmosis are forms of passive transport.
Explanation:
In diffusion, particles move from an area of higher concentration to one of lower concentration until equilibrium is reached.
In osmosis, a semipermeable membrane is present, so only the solvent molecules are free to move to equalize concentration.
Answer:
A tensor is a quantity, for example a stress or a strain, which has magnitude, direction, and a plane in which it acts. Stress and strain are both tensor quantities. ... A tensor is a quantity, for example a stress or a strain, which has magnitude, direction, and a plane in which it acts.
Inertia Tensor. where I = the inertia tensor. The angular momentum of a rigid body rotating about an axis passing through the origin of the local reference frame is in fact the product of the inertia tensor of the object and the angular velocity. ... As shown in [7], the inertia tensor is symmetric.
Explanation:
Hope dis help
Answer:
Abby is standing (4.5^2 + 2.3^2)^1/2 from the far speaker
D2 = 5.05 m from the far speaker
The difference in distances from the speakers is
5.05 - 4.5 = .55 m (Let y be wavelength, lambda)
n y = 4.5
(n + 1) y = 5.05 for the speakers to be in phase at smallest wavelength
y = .55 m subtracting equations
f = v / y = 340 / .55 = 618 / sec should be the smallest frequency
All you would do is for a, 10 times 2 is 20 so it would be 20-dB
For b, 10 times 4 is 40 so it would be 40-dB
<span>For c, 10 times 8 is 80 so it would be 80-dB</span>