Answer:
-1952
Step-by-step explanation:
Money offered to Michelle per annum in Job A = $1700
Number of years she will work in job A = 5
Percentage of earnings per annum for her retirement plan = 6.60%
Money she will earn will be the simple interest at the end of 5 years.
We know that :
![\color{plum}{ \tt{Simple \: interest = \frac{Principle \ \: \times \: Rate \: \: \times \: \: Time}{100} }}](https://tex.z-dn.net/?f=%5Ccolor%7Bplum%7D%7B%20%5Ctt%7BSimple%20%5C%3A%20%20interest%20%20%3D%20%20%5Cfrac%7BPrinciple%20%20%5C%20%5C%3A%20%5Ctimes%20%20%5C%3A%20Rate%20%20%5C%3A%20%20%5C%3A%20%5Ctimes%20%5C%3A%20%20%5C%3A%20%20Time%7D%7B100%7D%20%7D%7D)
Principal = $1700
Rate = 6.60%
Time = 5 years
Which means :
![= \frac{1700 \times 6.60 \times 5}{100}](https://tex.z-dn.net/?f=%20%3D%20%20%5Cfrac%7B1700%20%5Ctimes%206.60%20%5Ctimes%205%7D%7B100%7D%20)
![= \frac{56100}{100}](https://tex.z-dn.net/?f=%20%3D%20%20%5Cfrac%7B56100%7D%7B100%7D%20)
![= \color{plum}\$561](https://tex.z-dn.net/?f=%20%3D%20%5Ccolor%7Bplum%7D%5C%24561)
We also know that :
![\color{plum}\tt \: Amount = Principal + Interest](https://tex.z-dn.net/?f=%5Ccolor%7Bplum%7D%5Ctt%20%5C%3A%20Amount%20%3D%20Principal%20%2B%20Interest%20)
Amount Michelle will earn at the end of 5 years for her retirement plan :
![= 1700 + 561](https://tex.z-dn.net/?f=%20%3D%201700%20%2B%20561)
![=\color{plum}\bold{\$ 2261}](https://tex.z-dn.net/?f=%20%3D%5Ccolor%7Bplum%7D%5Cbold%7B%5C%24%202261%7D)
2261 can be rounded off to 2260.
Therefore, Michelle will earn <u>$2260</u> at the end of 5 years for her retirement plan.
Answer:
see the attachment
Step-by-step explanation:
Answer:
Yumiko should multiply the other equation by 3.
If she adds the two equations she would be left with the variable 'x'.
Step-by-step explanation:
Given the two equations are as follows:
![$ 2x - 3y = 12 \hspace{5mm} \hdots (1) $](https://tex.z-dn.net/?f=%24%202x%20-%203y%20%3D%2012%20%5Chspace%7B5mm%7D%20%5Chdots%20%281%29%20%24)
![$ 5x + 6y = 18 \hspace{5mm} \hdots (2) $](https://tex.z-dn.net/?f=%24%205x%20%2B%206y%20%3D%2018%20%5Chspace%7B5mm%7D%20%5Chdots%20%282%29%20%24)
It is given that she multiplies the first equation by 6. Therefore, (1) becomes
![$ 12x - 18y = 72 \hspace{15mm} \hdots (a) $](https://tex.z-dn.net/?f=%24%2012x%20-%2018y%20%3D%2072%20%5Chspace%7B15mm%7D%20%5Chdots%20%28a%29%20%24)
Now, note that the sign of the variable 'y' is negative. So, if we make the co-effecient of 'y' equal in both the cases, add them it would result in the elimination of the variable 'y'.
The co-effecient of y in Equation (2) is 6. To make it 18 like it is in Equation (1), we multiply throughout by 3.
Therefore, Equation (2) becomes:
![$ 15x + 18y = 54 \hspace{5mm} \hdots (b) $](https://tex.z-dn.net/?f=%24%2015x%20%2B%2018y%20%3D%2054%20%5Chspace%7B5mm%7D%20%5Chdots%20%28b%29%20%24)
Now, we add Equation (a) and Equation (b).
![$ \implies 12x - 18y + 15x + 18y = 72 + 54 $](https://tex.z-dn.net/?f=%24%20%5Cimplies%2012x%20-%2018y%20%2B%2015x%20%2B%2018y%20%3D%2072%20%2B%2054%20%24)
![$ \implies 27x = 126 $](https://tex.z-dn.net/?f=%24%20%5Cimplies%2027x%20%3D%20126%20%24)
Factor: 3
Equation: 27x = 126
Answer: 50 cents
Step-by-step explanation:
Company charges 8 cents per call and the call in question is 3 minutes. Cost is;
= 3 * 8
= 24 cents
Company however stipulates that a call is 8 cents per minute or a 50-cent minimum charge per completed call, whichever is greater.
<em>50 cents is greater than the per minute total charge of 24 cents so the cost will be 50 cents.</em>